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3 years ago

The sum of three consecutive integers is 267. What is the largest integer?

1 answer:

7 0

Let the integers be x + (x+1) + (x + 2)

x + (x+1) + (x + 2) = 267 

3x + 3 = 267 
3x = 264 
x = 88 

88+89+90=267 

Largest integer=90 

Another method 

267/3 = 89 

It's the average,so it has to be the middle one. 

Thus 89, then I took 89 - 1 = 88 and 89 + 1 = 90 and just put them in order. 

88+89+90=267 

Largest integer=90

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4-4x-9x how many terms

11Alexandr11 [23.1K]

Answer:

3 terms

Step-by-step explanation:

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2 years ago

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ExtremeBDS [4]

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2 years ago

Which of the following is a true statement about the symmetry of this figure?

katovenus [111]

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2 years ago

Read 2 more answers

A square of side length s lies in a plane perpendicular to a line L. One vertex of the square lies on L. As this square moves a

user100 [1]

Answer:

Part (A) The required volume of the column is $s^2h$ .

Part (B) The volume be $s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$ .

Step-by-step explanation:

Consider the provided information.

It is given that the we have a square with side length "s" lies in a plane perpendicular to a line L.

Also One vertex of the square lies on L.

Part (A)

Suppose there is a square piece of a paper which is attached with a wire through one corner. As you blow it up it spins around on the wire.

This square moves a distance h along L, and generate a corkscrew-like column with square.

The cross section will remain the same.

So the cross section area of original column and the cross section area of twisted column at each point will be the same.

The volume of the column is the area of square times the height.

This can be written as:

$s^2h$

Hence, the required volume of the column is $s^2h$ .

Part (B) What will the volume be if the square turns twice instead of once?

If the square turns twice instead of once then the volume will remains the same but divide the volume into two equal part.

$s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$

Hence, the volume be $s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$ .

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3 years ago

Explain how modeling partial products can be used to find the products of greater numbers ?

liq [111]

You can break large numbers into a sum of a multiple(s) of 10 and the last digit of the number. For example, you can break 26 as 20+6, or 157 as 100+50+7.

Then, using the distributive property, you can turn the original multiplication into a sum of easier multiplications. For example, suppose we want to multiply 26 and 37. This is quite challenging to do in your mind, but you can break the numbers as we said above:

$26\times 37=(20+6)(30+7) = 20\times 30+20\times 7+30\times 6+6\times 7$

All these multiplications are rather easy, because they either involve multiples of 10 of single-digit numbers:

$20\times 30+20\times 7+30\times 6+6\times 7 = 600+140+180+42=962$

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3 years ago