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Liula [17]
3 years ago
7

Select all the true statements.

Mathematics
1 answer:
Digiron [165]3 years ago
8 0

Answer:

The correct option are;

1) You can compare irrational numbers using rational approximations

2) Square roots can be compares and ordered by comparing and ordering the numbers underneath the radical symbol

3) The closer together the numbers being compared, the more decimal places you need to use

Step-by-step explanation:

1) Two irrational numbers can be compared using rational approximation because both rational and irrational numbers are part of the real numbers and therefore have defined positions on the real number line such that the values of rational and irrational numbers can be compared based on their relative position on the number line.

2) The values of a square roots is directly proportional to the value under the radical symbol, therefore, square roots can be arranged in their order of magnitude and can also be compared by comparing and ordering the numbers under the radical symbol

3) When two numbers are very close, the difference between the numbers will be small. Therefore in order to clearly define the differences between two close numbers, the value of the difference between the numbers needs to be amplified by increasing the detail or the number of decimal place values of the numbers

Similarly, comparing two numbers that are very close requires increasing the detail or the number of decimal place values of the numbers

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You must include in this exercise four short, clearly separated paragraphs (2-3 sentences) consisting of the concerns printed in bold:

1. description of the chosen image (include the image information: title, artist's name, year, medium, etc.) and say what you see.

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5 0
3 years ago
A rectangle's length is seven times its width. let w denote the rectangle's width. what polynomial represents the rectangle's ar
wolverine [178]

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6 0
4 years ago
\frac{1}{5}k-9=\frac{3}{5}k-7
Oksi-84 [34.3K]

let start by multiplying both sides by the LCD of all denominators, in this case that'd be 5, to do away with the denominators.


\bf \cfrac{1}{5}k-9=\cfrac{3}{5}k-7\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{5}}{5\left( \cfrac{1}{5}k-9 \right)=5\left( \cfrac{3}{5}k-7 \right)}\implies k-45=3k-35 \\\\\\ -45=2k-35\implies -10=2k\implies \cfrac{-10}{2}=k\implies -5=k

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3 years ago
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user100 [1]

Answer:

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Step-by-step explanation:

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3h+77=92-2h

-77. = -77

3h= 15-2h

+2h=+2h

5h=15

H=3

3 0
3 years ago
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