Answer:
Size of N(S) = 90, or S=90
Step-by-step explanation:
So since there are 10 items:
Each single item has 9 possibilities to be paired with, since it is drawn without replacement, and 1 item can't be drawn again.
So : 10 items x 9 possibilites = array of 90
SO ANSWER : 90
Hope I helped :)
Beer? at an electronic store? but srsly, 81*.07 is 5.67, total is 86.67
Answer:
true
Step-by-step explanation:
this is the answer that I think you are looking for.
Answer:
Step-by-step explanation:
If you can present a problem in Latex, you can do anything. I don't know what the question mark is for. I'm just ignoring it.
55 2/3 * 66 5/6
One of the ways to get the answer is to use decimals
55.666666667 * 66.833333333 = 3720.38889
Another way to do this problem is to break up one of the numbers
55 2/3 (66 + 5/6) You can do this if you know how to use the distributive property.
55 2/3 * 66 + 55 2/3 * 5/6
( (165 + 2) / 3) * 66 + (165 + 2)/3 * 5/6
167/3 * 66 + 167 / 3 * 5/6
167 * 22 + (167 * 5 / (3 * 6)
3674 + 835 / 18
3674 + 46 7/18
3720 7/18
If none of these seem right and you have choices, please list them.
Yes, I'm getting C also!
Since it's asking for the left-endpoint Riemann Sum, you will only be using the top left point as the height for each of your four boxes, making -1, -2.5, -1.5, and -0.5 your heights. The bases are all the same length of 2. You don't include f(8) because you're not using right-endpoints, and that would also add another 5th box that isn't included in the 0 to 8 range.
