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aivan3 [116]
3 years ago
12

a 2 kg rabbit starts from rest and its moving at 6 m/s after 3 seconds . what force must the rabbit cause to makes this change i

n speed
Physics
2 answers:
cestrela7 [59]3 years ago
5 0
1. Acceleration= change of speed over the time = from 0 to 6m/s in 3sec= 6/3= 2m/s^2
2. Force=mass times acceleration = 2kg times 2m/s^2 = 4 N
Answer 4N
Alborosie3 years ago
3 0
Gravity pulling it down or the air cd (carbon dioxide)
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A 0.12-kg metal rod carrying a current of current 4.1 A glides on two horizontal rails separation 6.3 m apart. If the coefficien
Neporo4naja [7]

Answer:

The magnetic field is B  =  8.20 *10^{-3} \  T

Explanation:

From the question we are told that

   The  mass of the metal rod is  m  = 0.12 \ kg

    The current on the rod is  I  = 4.1 \ A

    The distance of separation(equivalent to length of the rod ) is L   = 6.3 \ m

     The coefficient of kinetic friction is \mu_k  =  0.18

      The kinetic frictional force is  F_k  = 0.212 \ N

     The constant speed is v  = 5.1 \ m/s

Generally the magnetic force on the rod is mathematically represented as  

      F  =  B * I  *   L

For  the rod to move with a constant velocity the magnetic force must be equal to the kinetic frictional force so

        F_ k  =  B*  I  *  L

=>      B  =  \frac{F_k}{L  *  I  }

=>       B  =  \frac{0.212}{ 6.3   *  4.1   }

=>       B  =  8.20 *10^{-3} \  T

7 0
3 years ago
Give reason The SI system of unit is better than the MKS system​
egoroff_w [7]

Answer:

The SI was and is intended to extend and refine the definitions used by the MKS.

6 0
3 years ago
Does the vertical or horizontal position affect an objects potential energy?
son4ous [18]
Yes. If an object would be vertical, it would most likely have potential energy due to gravity. 
6 0
3 years ago
A wrecking ball is hanging at rest from a crane when suddenly the cable breaks. The time it takes for the ball to fall halfway t
Naddik [55]

Answer:

1.697s

Explanation:

We use the second equation of free fall under gravity as follows;

h=ut+\frac{1}{2}gt^2...............(1)

Since  the ball fell freely, u = 0m/s, therefore equation (1) reduces to

h=\frac{1}{2}gt^2...............(2)

Given that h is the total height the ball falls through in time t seconds.

However, according to the stated problem the ball falls halfway in 1.2s, this simply implies that the ball falls through a distance of \frac{h}{2} in 1.2s. Hence we can write the following, given that g=9.8m/s^2;

\frac{h}{2}=\frac{1}{2}*9.8*1.2^2\\hence\\h=9.8*1.2^2\\h=14.112m

We can now proceed to find the time t for which it falls through h = 14.112m as follows;

14.112=\frac{1}{2}*9.8*t^2\\14.112=4.9t^2\\t^2=\frac{14.112}{4.9}\\t^2=2.88\\t=\sqrt{2.88} \\t=1.697s

8 0
3 years ago
A 500 N weight is hung at the middle of a rope attached to two buildings at the same level. If the breaks in the tension exceed
dedylja [7]

Answer:

The correct choice is 8o.

Explanation:

The given weight is hanging at the mid point of the rope and the buildings are at the same level, Obtain the given equation by equating the vertical components of force,

2Tsin(φ)=W

where φ is the angle made by rope with the horizontal.

Given T=1800 N and W=500 N, the value of φ is calculated as follows,

2*1800*sin(φ)=500

sin(φ)=0.1388

φ=7.90

φ≈8o

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6 0
2 years ago
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