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Hunter-Best [27]
2 years ago
6

Men’s heights are normally distributed with a mean of 71.8 inches and a standard deviation of 3.4 inches. A social organization

for short people has a requirement that men must be at most 65 inches tall. What percentage of men meet this requirement?
Mathematics
1 answer:
nadya68 [22]2 years ago
8 0

Answer: 2.28%

Step-by-step explanation:

μ = 71.8

σ = 3.4

X < 65

P(X < 65) = P (Z < 65 - 71.8/3.4) = P (Z < -2)

According to the table for the normal distribution attached, it will give us

P (z < Z < 0), this way, to find the P(Z < z), we need to do 0.5 - P:

0.5 - P(-2 < Z < 0) = 0.5 - 0.4772 = 0.0228

In percentage: 0.0228*100 = 2.28%

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The simplest interpretation would go a little something like this:

We know that we want the total donation amount to be more than $7,900, so we can set up this inequality to begin with

D \ \textgreater \ 7,900

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3 years ago
The ratio of tom’s age to Mary’s is 3:4.If Tom is 15 how old is Mary
AnnZ [28]
Hey there!

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I hope this helps!
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