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Hunter-Best [27]
2 years ago
6

Men’s heights are normally distributed with a mean of 71.8 inches and a standard deviation of 3.4 inches. A social organization

for short people has a requirement that men must be at most 65 inches tall. What percentage of men meet this requirement?
Mathematics
1 answer:
nadya68 [22]2 years ago
8 0

Answer: 2.28%

Step-by-step explanation:

μ = 71.8

σ = 3.4

X < 65

P(X < 65) = P (Z < 65 - 71.8/3.4) = P (Z < -2)

According to the table for the normal distribution attached, it will give us

P (z < Z < 0), this way, to find the P(Z < z), we need to do 0.5 - P:

0.5 - P(-2 < Z < 0) = 0.5 - 0.4772 = 0.0228

In percentage: 0.0228*100 = 2.28%

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A monk crossbred plants which can have purple or white flowers and obtained 511 plants with white flowers and 337 plants with pu
Zepler [3.9K]

Answer:

For purple;

P(p) = 337/848 = 0.40

For white;

P(w) = 511/848 = 0.60

Step-by-step explanation:

Given;

Number of plants with purple flowers P = 337

Number of plants with white flowers W = 511

Total T = 337 + 511 = 848

For purple;

the empirical Probability that a plant had purple flowers P(p) is

P(p) = Number of plants with purple flowers/total number of plants

P(p) = P/T

Substituting the values, we have;

P(p) = 337/848 = 0.40

For white;

the empirical Probability that a plant had white flowers P(w) is

P(w) = Number of plants with white flowers/total number of plants

P(w) = W/T

Substituting the values, we have;

P(w) = 511/848 = 0.60

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