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Hunter-Best [27]
3 years ago
6

Men’s heights are normally distributed with a mean of 71.8 inches and a standard deviation of 3.4 inches. A social organization

for short people has a requirement that men must be at most 65 inches tall. What percentage of men meet this requirement?
Mathematics
1 answer:
nadya68 [22]3 years ago
8 0

Answer: 2.28%

Step-by-step explanation:

μ = 71.8

σ = 3.4

X < 65

P(X < 65) = P (Z < 65 - 71.8/3.4) = P (Z < -2)

According to the table for the normal distribution attached, it will give us

P (z < Z < 0), this way, to find the P(Z < z), we need to do 0.5 - P:

0.5 - P(-2 < Z < 0) = 0.5 - 0.4772 = 0.0228

In percentage: 0.0228*100 = 2.28%

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Consider two people being randomly selected. (For simplicity, ignore leap years.)
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Answer:

(a) = \frac{144}{133225} \\\\(b) = \frac{1}{365}

Step-by-step explanation:

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Neglecting leap year, there are 365 days in a year.

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= \frac{365}{365} X \frac{364}{365} =\frac{364}{365}

P(2 people selected have birthday on the same day of same month) = 1-\frac{364}{365} \\\\= \frac{1}{365}

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