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3 years ago

ANSWER FAST PLZ 25POINTS!!!!!!!!!!!

Mathematics

2 answers:

Gre4nikov [31]3 years ago

5 0

Answer:

Step-by-step explanation:

43.96 in. divided by 3.14 = 14/2 = 7

The radius is 7in

nadezda [96]3 years ago

3 0

Answer:

7 inches, B

Step-by-step explanation:

The circumference of a circle is equal to 2*pi*r, and pi=3.14.

Set 43.96 equal to 2*3.14*r, dividing by 2*3.14, r=7 inches, or B.

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Lara wants to inscribe a square in a circle using only a compass and straightedge. She will first construct a circle and locate

Mamont248 [21]

In Step 2, Lara did not ensure that the second diamter was perpendicualr to the first diameter she drew.

The correct steps should be:

Step 1: Use the straightedge to draw a diameter of the circle. Label the points at which the diameter touches the circle as A and B.

Step 2: Draw a second diameter <em>perpendicular to the first diameter</em>. Label the points at which the second diameter touches the circle as C and D.

Step 3: Join the end points of the two diameters to form a square.

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3 years ago

A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

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Answer:

option d.

Step-by-step explanation:

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