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3 years ago

Classify a triangle with angle measures of 63 degrees and 27 degrees.

Mathematics

2 answers:

ycow [4]3 years ago

7 0

Answer:

Right triangle

Step-by-step explanation:

First angle of triangle = 63°

Second angle of triangle = 27°

Third angle of triangle = 180°-(63°+27°) = 90° ∴sum of three angle of triangle is 180°

As one angle is 90°(right angle), therefore it is a right triangle.

Maksim231197 [3]3 years ago

3 0

Answer:

right

Step-by-step explanation:

The sum of all three angle measures in a triangle will always equal 180 degrees. So, if you subtract 63 and 27 from 180 you will have your third angle measure, which is 90.

So now your 3 measures are 63, 27, and 90. Since one of the angles is a 90-degree angle, the triangle must be a right angle because a right angle has a measure of 90 degrees.

I hope this helps!

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2 years ago

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2 years ago

Line segment CD is shown on a coordinate grid:

Lady_Fox [76]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Please show your work

Effectus [21]

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2 years ago

A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben

juin [17]

Answer:

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

5 0

3 years ago