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Amiraneli [1.4K]
3 years ago
6

Ray UW is the angle bisector of VUT.

Mathematics
2 answers:
aliina [53]3 years ago
4 0

Answer:

38°

Step-by-step explanation:

An angle bisector divides the angles into 2 equal parts. Since ray UW is the angle bisector of ∠VUT, it divides ∠VUT into two equal angles ∠VUW and ∠WUT

We are given the measures of both angles.

mVUW = (4x + 6)°  

mWUT = (6x – 10)°

Since,

mVUW = mWUT, we can write:

4x + 6 = 6x - 10

6 + 10 = 6x - 4x

16 = 2x

x = 8

Using the value of 8 in equation of mWUT, we get:

mWUT = (6x – 10)°

= 6(8) - 10

= 48 - 10

= 38°

Thus, the measure of WUT is 38°

kifflom [539]3 years ago
4 0

Answer:

38°

Step-by-step explanation:

Given: Ray UW is the angle bisector of VUT, \angle \text{WUT}=(6x-10)^{\circ}  and \angle \text{VUW}=(4x+6)^{\circ}

To find: Measure of WUT

Solution: Consider the figure in the attached pic.

We know that the angle bisector will divide the angle into two equal halves.

So, we have \angle \text{WUT}=\angle \text{VUW}

Here, \angle \text{WUT}=(6x-10)^{\circ} , and \angle \text{VUW}=(4x+6)^{\circ}

So, we have

6x-10=4x+6

6x-4x=10+6

2x=16

x=8

So, \angle \text{WUT}=(6x-10)^{\circ}=6\times8-10=38^{\circ}

Hence, \angle \text{WUT}=38^{\circ}

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Step-by-step explanation:

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I have 31 stamps in total. I have 4 more 1 cent stamps than 8 cent stamps and twice as many one cent stamps as 12 cent stamps. I
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Answer:

There area 14 one cent stamps

Step-by-step explanation:

Let

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z -----> the number of 12 cent stamps

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Read 2 more answers
If the area of a rectangle in terms of x is x2 + 15x + 26 / 6x2 and its width is x2 - 3x - 10 / 30x3 Find the length of the rect
Veseljchak [2.6K]

Answer:

The length of the rectangle is;

5x(x+13)/(x-5)

Step-by-step explanation:

Mathematically, we know that the area of a rectangle is the product of the length and width of the triangle

To find the length of the rectangle, we will have to divide the area by the width

we have this as;

(x^2 + 15x + 26)/6x^2 divided by (x^2-3x-10)/30x^3

thus, we have ;

(x^2 + 15x + 26)/6x^2 * 30x^3/(x^2-3x-10)

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(x^2-3x-10) = (x+2)(x-5)

Substituting the linear products in place of the trinomials, we have;

(x+2)(x+13)/(x+2)(x-5) * 5x

= 5x(x+13)/(x-5)

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