Gr terlarut = 36 gr
<span>Mr terlarut = 180 </span>
<span>gr pelarut = 250 gr </span>
<span>Kb air = 0,52 °C kg/mol </span>
<span>Tb larutan = ........? </span>
<span>--------------------------------------... </span>
<span>ΔTb = Kb.m.i </span>
<span>ΔTb = Kb. (gr t / Mr t) . (1000/ gr p) .i </span>
<span>ΔTb = 0,52 x (36/180) x (1000/250) x 1 </span>
<span>ΔTb = 0,416 °C </span>
<span>Tb = 100 + ΔTb </span>
<span>Tb = 100 + 0,416 </span>
<span>Tb = 100,416 °C</span>
It's 10.
Mass = density x volume
M = 1g/ml(10ml) = 10g
A) Metal has luster
Metals are ductile, malleable, and good conductors of heat.
Answer : The initial temperature of system 2 is, 
Explanation :
In this problem we assumed that the total energy of the combined systems remains constant.
The mass remains same.
where,
= heat capacity of system 1 = 19.9 J/mole.K
= heat capacity of system 2 = 28.2 J/mole.K
= final temperature of system =
= initial temperature of system 1 =
= initial temperature of system 2 = ?
Now put all the given values in the above formula, we get
Therefore, the initial temperature of system 2 is, 