Can someone help me please

Chemistry

1 answer:

deff fn [24]3 years ago

6 0

Answer:

What is we doing explain first before you say you need help with.

Explanation:

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What has to be true in order for a single replacement reaction to happen?

ella [17]

Answer: A

Explanation:

One element replaces another in a compound.

4 0

2 years ago

If you were running an experiment to determine the temperature at which beans sprouted (germinated) the fastest, what would be t

oksano4ka [1.4K]

Answer:

Temperature on beans sprouted

Explanation:

The variable amount is the amount that changes continuously.
We calculate the sprout of the bean at which temperature it is sprouting rapid, in that case, the temperature acts as a variable amount.

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4 years ago

For the reaction shown, identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. KNO3 →

Vinvika [58]

Answer : The oxidizing element is N and reducing element is O.

$KNO_{3}$ is act as an oxidizing agent as well as reducing agent.

Explanation :

An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.

Reducing agent is the agent which has ability to reduce other or lower in oxidation number.

The given reaction is :

$KNO_{3} \rightarrow KNO_{2} +O_{2}$

$KNO_{3}$ act as an oxidizing agent.

The oxidation number of N in $KNO_{3}$ is calculated as:

(+1)+(x)+3(-2) = 0

x = +5

And the oxidation number of N in $KNO_{2}$ is calculated as:

(+1)+(x)+2(-2) = 0

x = +3

From the oxidation number method, we conclude that the oxidation number reduced this means $KNO_{3}$ itself get reduced to $KNO_{2}$ and it can act as an oxidizing agent.

$KNO_{3}$ act as a reducing agent.

$KNO_{3} \rightarrow KNO_{2} +O_{2}$

The oxidation number of O in $KNO_{3}$ is calculated as:

(+1)+(+5)+3(x) = 0

x = -2

The oxidation number of O in $O_{2}$ is Zero (o).