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2 years ago

1. What is the degree of the polynomial below? X^3+2x-3x^4+5+3x^2

Mathematics

1 answer:

Maurinko [17]2 years ago

3 0

Answer:

Step-by-step explanation:

$x^3+2x-3x^4+5+3x^2 \\ degree \: of \: polynomial = 4$

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martin spent 6 hours on homework every day . what percentage of the day did martin spend doing homework ?

Ann [662]

1/4 or .25 because 6 * 4 = 24 so 6 would be a quarter of 24

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2 years ago

Ms Lewis is hiring a carpenter to repair her shed the cost of carpenter L is shown in the table

KiRa [710]

Based on the information given, it can be deduced that the initial cost will be $187 and the hourly rate is $72 per hour.

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Therefore, the rate per hour will be:

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The equation will then be:

= 187 + 72h

Lastly, the difference in the costs is $72.

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2 years ago

HELP will give brainliest if all correct

ladessa [460]

1. Definition of Parallelogram

2. Angle 2 plus Angle 3 is 180=Def of Supple

3.Angle Congruence Postulate

4. Angle 1 and Angle 3 equal to 180

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3 years ago

preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha

VladimirAG [237]

Answer:

$n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79$

n=369

Step-by-step explanation:

1) Notation and definitions

$X=40$ number of the selected labourers opt for a new incentive scheme.

$n=100$ random sample taken

$\hat p=\frac{40}{100}=0.4$ estimated proportion of the selected labourers opt for a new incentive scheme.

$p$ true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: