Answer:
<h3><ABC > <DBC.</h3>
Step-by-step explanation:
Given < DBC = < RST and we need to prove < ABC is greater than <RST.
First given statement:
< DBC = < RST
Reason: Given.
Second given statement :
<ABC = <DBC+ <ABD.
Reason: Angle addition theorem.
<em>Note: < ABC is the sum of angles <DBC and <ABD and we have < DBC = < RST. So it's an obvious thing that the sum of angles <DBC and <ABD is always greater than <RST.</em>
Also, <ABC is greater than <DBC.
Therefore, correct option for third statement is :
<h3><ABC > <DBC.</h3>
Answer:
f(3) = 36
Step-by-step explanation:
ƒ(x) = 5x^2 − 9x + 18
Let x =3
ƒ(3) = 5(3)^2 − 9(3) + 18
= 5*9 -27 +18
= 45 -27+18
=36
Area of the polygon defined by the given points is 62.5 sq units
Step-by-step explanation:
Step 1 :
Let P be the point (-5,0) Q = (0,-5), R = (-15,-20) and S = (20,-15)
We have to to find the area of the polygon PQRS
Step 2 :
The area of polygon given the vertices (x
is given by
Area = mod (
) ÷ 2
Where
is the vertex n's x coordinate ,
is the vertex n's y coordinate
Substituting the corresponding values ,
Area of PQRS = mod ( (25 - 0)+ (0-75) +(300-300) +( 0-75) ) ÷ 2
= mod (25-75+0-75) ÷ 2
= mod (-125) ÷ 2 = 125 ÷ 2 = 62.5 sq units
Step 3 :
Answer :
Area of the polygon defined by the given points is 62.5 sq units
Since a fraction is a form of division, you do 21/2=10 and 1/2.
Maggie =x
brother = 2x-3
x+2x-3= 24
27 /3= 3 x/3
x= 9 years