Question

Triangle A B C. Angle C is 90 degrees. Hypotenuse A B is 26, adjacent side A C is 24, opposite C B is 10. For the triangle above, find sin A. a. 36° c. 0.9323 b. 50° d. 0.385

Answer 1

Answer:

Option (D).

Step-by-step explanation:

In the figure attached,

ΔACB is a right triangle with AC = 24 units, BC = 10 units and AB = 26 units

For angle A,

Adjacent side = AC

Opposite side = BC

Hypotenuse = AB

SinA = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

        = $\frac{BC}{AB}$

        = $\frac{10}{26}$

SinA = 0.3846

        ≈ 0.385

Therefore, Option (D) will be the answer.