It would be 2/10, or 1/5, since two out of the 10 numbers are even. 2/10 simplifies to 1/5, since there is 1 for every 5 numbers.
We could turn this into a percentage by dividing 1 by 5, which gives us 0.2. Then we can multiply by 100 to get 20.
So, our probability of choosing an even number is:
2/10
OR
1/5
OR
20%
Hope I could help!
Solution
The 1st term = -3
15th term = 53
15th term = a + d(n-1)
53 = -3 + d(15- 1) [Here n = 15)
53 + 3 = d(14)
14d = 56
d = 4
The common difference is 4.
