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2 years ago

What is the simplest form of the quotient 4 square root 810 over 4 square root 2

Mathematics

1 answer:

Len [333]2 years ago

3 0

Answer:

$3\sqrt[4]{5}$

Step-by-step explanation:

Given: $\frac{\sqrt[4]{810} }{\sqrt[4]{2} }$

Top and bottom has fourth root. so we take fourth root in common

$\sqrt[4]{\frac{810}{2} }$

When we divide 810 by 2. we will get 405

$\sqrt[4]{405}$

Now we simplify the fourth root

405 can be written as 3*3*3*3*5

$\sqrt[4]{3*3*3*3*5}$

$3\sqrt[4]{5}$

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All tubes of watercolor paint at an art supply store have the the same price. An artist has a coupon for $0.50 off each tube of

BlackZzzverrR [31]

Let us assume the regular price of each tube of paint = r.

0.50 off each tube.

New price of each tube = r - 0.50.

She buy 6 tubes.

Total price of 6 tubes = 6×(r-0.50).

We are given total price = $84.30 .

Therefore, we can setup an equation

6×(r-0.50) = 84.30.

Distributing 6 over (r-0.50), we get

6r - 3.0 = 84.30

Adding 3.0 on both sides, we get

6r - 3.0+3.0 = 84.30+3.0

6r = 87.30

Dividing both sides by 6, we get

6r/6 = 87.30/6

r = 14.55

<h3>Therefore, required equation is 6(r-0.50) = 84.30 and the regular price of each tube of paint is $14.55.</h3>

5 0

3 years ago

Need help now!! 20 points!!

Gelneren [198K]

When you have something like this, all you need to do is substitute the values, the last is for what value of x

For the first one;

((x^2+1)+(x-2))(2)

(x^2+x-1)(2)

(2)^2+(2)-1

4+2-1

For the second one;

((x^2+1)-(x-2))(3)

(x^2-x+3)(3)

(3)^2-(3)+3

9-3+3

For the last one;

3(x^2+1)(7)+2(x-2)(3)

3((7)^2+7)+2((3)-2)

3(49+7)+2(3-2)

3(56)+2(1)

168+2

170

3 0

2 years ago

All bags entering a research facility are screened. The screening process is not perfect so that 77% of the bags that contain fo

garik1379 [7]

Answer:

(1) 0.5933

(2) 0.8955

Step-by-step explanation:

We are given that all bags entering a research facility are screened.

Let Probability that bags entering the building contains forbidden material,

P(F) = 0.69

Probability that bags entering the building does not contains forbidden material, P(NF) = 1 - 0.69 = 0.31

Let event A = alarm gets triggered

Probability that alarm gets trigger given the bags contain forbidden material, P(A/F) = 0.77

Probability that alarm gets trigger given the bags does not contain forbidden material, P(A/NF) = 0.20

(1) Probability that a bag triggers the alarm, P(A) ;

P(A) = P(F) * P(A/F) + P(NF) * P(A/NF)

= (0.69 * 0.77) + (0.31 * 0.20) = 0.5313 + 0.062

= 0.5933

Therefore, probability that a bag triggers the alarm is 0.5933 .

(2) Probability that a bag that triggers the alarm will actually contain forbidden material is given by P(F/A) ;

Using Bayes' Theorem;

P(F/A) = $\frac{P(F) * P(A/F)}{P(F) * P(A/F) + P(NF) *P(A/NF)}$ = $\frac{0.69*0.77}{0.69*0.77+0.31*0.20}$ = $\frac{0.5313}{0.5933}$

= 0.8955

6 0

3 years ago

A rectangle with sides of lengths 4/5 foot and 1/2 foot

Nadusha1986 [10]

The area would be .4 cubic feet. The perimeter would be 2.1

8 0

3 years ago

(1+1/3)^2−2/9 I am about to have a mental breakdown, please somebody answer

Archy [21]

Answer:

$\frac{14}{9} = 1\frac{5}{9} \\\\1.5$

Step-by-step explanation:

$(1+1/3)^2-2/9\\\\= \left(1+\frac{1}{3}\right)^2-\frac{2}{9}\\\\\left(1+\frac{1}{3}\right)^2=\frac{4^2}{3^2}\\\\=\frac{4^2}{3^2}-\frac{2}{9}\\\\\frac{4^2}{3^2}=\frac{16}{9}\\\\=\frac{16}{9}-\frac{2}{9}\\\\\mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\\\=\frac{16-2}{9}\\\\\mathrm{Subtract\:the\:numbers:}\:16-2=14\\=\frac{14}{9}$

8 0

3 years ago

Read 2 more answers