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VashaNatasha [74]
4 years ago
6

The table below lists the properties of a metallic element. (Shiny, silver colored, forms +1 and +2 ions, and compound with sulf

ur is bright red)
Where on the periodic table can this element most likely be found?
Group 1
Group 2
Group 12
Group 13
Chemistry
2 answers:
iren [92.7K]4 years ago
5 0

Answer:

Group 12, element is mercury

Explanation:

Elements of group 12 are Zn, Cd and Hg.

Valence shell electronic configuration of group 12 elements is: (n-1)d^{10}ns^2

Elements of group 12 elements generally exist in +2 oxidation states in their compounds.

However, Hg also form series of compounds in which oxidation state of Hg is +1.

For example, Hg_2Cl_2\ and\ HgCl_2

Mercury is a shiny silver colured.

When mercury reacts with sulfur, a odorless red colored ppt is formed.

So among given option, group 12 is the correct answer and element is mercury.

Triss [41]4 years ago
4 0

Answer:

Group 13

Explanation:

We have been given some properties of the elements we desire to identify.

The most important and by far unique is the oxidation state of the ions given. This reflects the amount of electrons an atom has lost or gained.

Group 1 and 2 elements have oxidation states of +1 and +2 respectively. This is a very perculiar property of these metals. When group 1 elements lose an electron, nobility is achieved and this goes for group 2 elements too.

Group 12 consists of transition elements. Most transition elements are known to have variable oxidation states. In this group, the common oxidation state is +2.

Group 13 elements have two dominant oxidation numbers which are +1 and +3. Particularly, Aluminum has +2 oxidation state too.

The properties fits in well for aluminum which is a group 13 element.

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Answer:

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6 0
3 years ago
Read 2 more answers
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vovangra [49]

Answer:

24805.44 J

Explanation:

Step 1:

Data obtained from the question.

Mass (M) = 464g

Initial temperature (T1) = 120°C

Final temperature (T2) = 219°C

Change in temperature (ΔT) = T2 - T1 = 219°C - 120°C = 99°C

Specific heat capacity of lead (C) = 0.129cal/g°C = 4.184 x 0.129 = 0.54J/g°C

Heat (Q) =?

Step 2:

Determination of the heat Q, required the temperature of lead. This is illustrated below

Q = MCΔT

Q = 464 x 0.54 x 99

Q = 24805.44 J

Therefore, 24805.44 J of heat is required to raise the temperature of lead.

5 0
3 years ago
How many atoms are in 3.5 moles of arsenic atoms?
solmaris [256]

Answer:

2.107×10²⁴

Explanation:

no of moles=no of particles/Avogadro's number

3.5=X/6.02×10²³

by cross multiplication

3.5×6.02×10²³

=2.107 ×10²⁴

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3 years ago
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The specific heat capacity of a certain type of cooking oil is 1.75 J/(g⋅∘C). What is the amount of heat exchanged when the temp
anygoal [31]

Answer:

Q = -811440 J

Explanation:

Given data:

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Initial temperature = 191 °C

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Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

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ΔT = -168°C

Q = 2760 g ×1.75 J/g.°C  ×-168°C

Q = -811440 J

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3 years ago
Please help me with this. Thanks
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The third one because

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3 years ago
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