H₂SO₄:
V=0,95L
Cm=0,420mol/L
n = CmV = 0,42mol/L * 0,95L = 0,399mol
KOH:
V=0,9L
Cm=0,26mol/L
n = CmV = 0,26mol/L * 0,9L = 0,234mol
H₂SO₄ + 2KOH ⇒ K₂SO₄ + 2H₂O
1mol : 2mol
0,399mol : 0,234mol
limiting reagent
reamins: 0,399mol - 0,117mol = 0,282mol
n = 0,282mol
V = 0,950L + 0,900L = 1,85L
Cm = n / V = 0,282mol / 1,85L ≈ 0,152M
I believe it is spontaneous generation
Answer:
<h2>377 kPa</h2>
Explanation:
The original pressure can be found by using the formula for Boyle's law which is

where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we're finding the original pressure

150 kPa = 150,000 Pa
We have

We have the final answer as
<h3>377 kPa</h3>
Hope this helps you
There are three carbon and 8 hydrogen present in propane molecule. The Lewis structure of propane is shown as:
Three molecules of such carbon atoms bound to eight molecules with hydrogen atoms make up the organic complex propane molecule.
It is known that carbon has 4 valence electrons and hydrogen has one valence electron. Carbon needs 4 extra electrons to complete its octet hence, it will share its electrons with with 4 hydrogen atom and complete its octet.
Carbon will be formed 4 bond . Three bond with hydrogen and one bond with carbon atom.
To know more about Lewis structure.
brainly.com/question/15837141
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<span>1.)One way to limit iron corrosion is to coat the iron with a metal that:
A.)will never undergo corrosion
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