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3 years ago

How does an increase in reactant concentration affect the rate of reaction?

Chemistry

2 answers:

ExtremeBDS [4]3 years ago

6 0

Answer:

It leads to more frequent collisions, which increase reaction rate

Explanation:

An increase in reactant concentration leads to an increase in reactant particles which increases the number of collision in a reaction and then causes a reaction to proceed faster.

This belief was first suggested by the collision theory which states that for a reaction to occur, the reacting particles must collide with one another. However, further studies show that not all collisions lead to a reaction, and only effective collisions lead to a reaction.

Hence, an increase in reactant concentration increases the frequency of collision which in turn increases the chances of effective collision and subsequently sincreases the reaction rate.

maxonik [38]3 years ago

6 0

Answer:

The correct answer is Option A

It leads to more frequent collisions, which increase reaction rate.

Explanation:

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Write the equilibrium constant expression for the following reaction in terms of concentrations of the components. (Concentratio

timofeeve [1]

<u>Answer:</u> The expression for equilibrium constant in terms of concentration is $K_c=[CO_2]$

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients. It is represented by $K_{c}$

For a general chemical reaction:

$aA+bB\rightarrow cC+dD$

The $K_{c}$ is written as:

$K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

The concentration of pure solids and pure liquids are taken as 1.

For the given chemical reaction:

$MgCO_3(s)\rightarrow MgO(s)+CO_2(g)$

The expression for $K_{c}$ is:

$K_{c}=\frac{[MgO][CO_2]}{[MgCO_3]}$

In the above expression, magnesium oxide and magnesium carbonate will not appear because they are present in solid state.

So, the expression for $K_c$ becomes:

$K_{c}=[CO_2]$

Hence, the equilibrium constant for the reaction is given above.

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3 years ago

Which has a greater density: an extremely small diamond used for industrial purpose such as grinding or a two-carat diamond take

ExtremeBDS [4]

The question is incomplete, the complete question is shown in the image attached to this answer

Answer:

See explanation

Explanation:

15) The both diamonds- the diamond used as a grinding tool and the two -carat diamond both have the same density because density is an intensive or intrinsic property of a substance. It does not depend on the mass of the substance present.

16) Area of magnesium = Length * width = 0.104 * 10^2 cm * 2.52 * 10^-1 cm = 2.62 cm^2

Density = mass/area * thickness

Density * area * thickness = mass

thickness = mass/Density * area

thickness = 0.104 g/ 1.74g/cm3 * 2.62 cm^2

thickness = 0.0228 cm