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expeople1 [14]
2 years ago
14

How many moles of ammonia, NH,, are contained in 6.21 x 1024 molecules of ammonia?

Chemistry
1 answer:
ankoles [38]2 years ago
6 0

Answer:

10.32 moles of ammonia NH₃

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 6.21×10²⁴ molecules

Number of mole of NH₃ =?

The number of mole of NH₃ can be obtained as follow:

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole

Therefore,

6.21×10²⁴ molecules = 6.21×10²⁴ / 6.02×10²³

6.21×10²⁴ molecules = 10.32 moles

Thus, 6.21×10²⁴ molecules contains 10.32 moles of ammonia NH₃

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Answer:

Explanation:

Word equation:

sulfuric acid + ammonium hydroxide  →  ammonium sulfate + water

Chemical equation:

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Balanced chemical equation:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O

The given reaction is the reaction of acid with base. When acid and base react salt and water are produced. In given reaction an acid sulfuric acid and base ammonium hydroxide react and form ammonium sulfate salt and water. The given reaction also follow the law of conservation of mass.

Steps to balance the equation:

Steps 1;

H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O

H = 7                            H = 10

S = 1                             S = 1

O = 5                           O = 5

N = 1                            N = 2

Step 2:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + H₂O

H = 12                            H = 10

S = 1                             S = 1

O = 6                           O = 5

N = 2                           N = 2

Step 3:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O

H = 12                            H = 12

S = 1                               S = 1

O = 6                             O = 6

N = 2                             N = 2

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