Help me idk what it means

Xinxuweisddeueyehcjduxhx

Tamiku [17]

Answer:

<h3>6 is the answer.</h3>

5 0

3 years ago

Read 2 more answers

the weights of bags of baby carrots are normally distributed, with a mean of 34 ounces and a standard deviation of .35 ounces. b

taurus [48]

Answer:

The carrots can weight atmost 34.59 ounces so that it does not need to be repackaged.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 34 ounces

Standard Deviation, σ = 0.35 ounces

We are given that the distribution of weights of bags is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.045

$P( X > x) = P( z > \displaystyle\frac{x - 34}{0.35})=0.045$

$= 1 -P( z < \displaystyle\frac{x - 34}{0.35})=0.045$

$=P( z < \displaystyle\frac{x - 34}{0.35})=0.955$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 34}{0.35} = 1.695\\\\x = 34.59325\approx 34.59$

Thus, the carrots can weight atmost 34.59 ounces so that it does not need to be repackaged.

5 0

3 years ago

Why is a sequence a function and how can you write a rule for a sequence?

statuscvo [17]

Certain sequences (not all) can be defined (expressed) in a "recursive" form. 
In a recursive formula, each term is defined as a function of its preceding term(s). 
[Each term is found by doing something to the term(s) immediately in front of that term.] 
A recursive formula designates the starting term, a1, and the nth term of the sequence, an , as an expression containing the previous term (the term before it), an-1.

The process of recursion can be thought of as climbing a ladder.
To get to the third rung, you must step on the second rung. Each rung on the ladder depends upon stepping on the rung below it.You start on the first rung of the ladder. a1
From the first rung, you move to the second rung. a2
 a2 = a1 + "step up"
From the second rung, you move to the third rung. a3
 a3 = a2 + "step up"
If you are on the nth rung, you must have stepped on the n-1st rung. an = an-1 + "step up"Notation: Recursive forms work with the term(s) immediately in front of the term being examined. The table at the right shows that there are many options as to how this relationship may be expressed in notations.A recursive formula is written with two parts: a statement of the first term along with a statement of the formula relating successive terms.The statements below are all naming the same sequence:Given TermTerm in front
of Given Terma4a3anan-1an+1anan+4an+3f (6)f (5)f (n)f (n-1)f (n+1)f (n)

 Sequence: {10, 15, 20, 25, 30, 35, ...}. Find a recursive formula.
This example is an arithmetic sequence (the same number, 5, is added to each term to get to the next term).

7 0

3 years ago

Four more than a number is no more than thirteen

Gemiola [76]

If x+4>13 then it would be x>9

8 0

3 years ago

Read 2 more answers

The table showing the stock price changes for a sample of 12 companies on a day is contained in the Excel file below.

AfilCa [17]

Answer:

(a) The sample variance for the daily price change is 0.2501.

(b) The sample standard deviation for the daily price change is 0.5001.

(c) The 95% confidence interval estimates of the population variance is (0.1255, 0.7210).

Step-by-step explanation:

Let the random variable X denote the stock price changes for a sample of 12 companies on a day.

The data provided is:

X = {0.82 , 1.44 , -0.07 , 0.41 , 0.21 , 1.33 , 0.97 , 0.30 , 0.14 , 0.12 , 0.42 , 0.15}

(a)

The formula to compute the sample variance for the daily price change is:

$s^{2}=\frac{1}{n-1}\sum\limits^{12}_{i=1}{(X_{i}-\bar X)^{2}}$

The sample mean is computed using the formula:

$\bar X=\frac{1}{n}\sum\limits^{12}_{i=1}{X_{i}}$

Consider the Excel output attached below.

In Excel the formula to compute the sample mean and sample variance are:

$\bar X$ =AVERAGE(A2:A13)

$s^{2}$ =VAR.S(A2:A13)

Thus, the sample variance for the daily price change is 0.2501.

(b)

The formula to compute the sample standard deviation for the daily price change is:

$s=\sqrt{\frac{1}{n-1}\sum\limits^{12}_{i=1}{(X_{i}-\bar X)^{2}}}$

Consider the Excel output attached below.

In Excel the formula to compute the sample standard deviation is:

$s$ =STDEV.S(A2:A13)

Thus, the sample standard deviation for the daily price change is 0.5001.

(c)

The (1 - α)% confidence interval for population variance is:

$CI=[\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2} } \leq \sigma^{2}\leq \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2} } ]$

Compute the critical value of Chi-square for α = 0.05 and (n - 1) = (12 - 1) = 11 degrees of freedom as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2,11}=21.920$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{(1-0.05/2),11}=\chi^{2}_{0.975,11}=3.816$

*Use a Chi-square table.

Compute the 95% confidence interval estimates of the population variance as follows:

$CI=[\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2} } \leq \sigma^{2}\leq \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2} } ]$

$=[\frac{(12-1)\times 0.2501}{21.920 } \leq \sigma^{2}\leq \frac{(12-1)\times 0.2501}{3.816} ]$

$=[0.125506\leq \sigma^{2}\leq 0.720938]\\\approx [0.1255, 0.7210]$

Thus, the 95% confidence interval estimates of the population variance is (0.1255, 0.7210).

7 0

4 years ago