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yKpoI14uk [10]
3 years ago
12

At the zoo tje ratio of snakes to lizards is 3:2 A. If there were 10 lizards ,how many snakes would be there be? B.If there were

9 snakes ,how many lizards would there be? C.If the number of snakes in the zoo is increased by 6, how many more lizards would the zoo need to get to keep the same ratio? D. If the total number of snakes ang lizards at the zoo was 20, how many snakes and lizards would there be? WITH CALCULATION AND STEPS PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0

Answer:

Part A) 15\ snakes

Part B) 6\ lizards

Part C) The zoo would need to get four more lizards to maintain the same proportion

Part D) 12 snakes and 8 lizards

Step-by-step explanation:

Part A) If there were 10 lizards ,how many snakes would be there be?

Let

x ---> the number of snakes

y ---> the number of lizards

\frac{x}{y}=\frac{3}{2} ----> equation A

we have that

y=10\ lizards

substitute the value of y in the equation A

\frac{x}{10}=\frac{3}{2}

solve for x

x=10(3)/2\\x=15\ snakes

Part B) If there were 9 snakes ,how many lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

\frac{x}{y}=\frac{3}{2} ----> equation A

we have that

x=9\ snakes

substitute the value of x in the equation A

\frac{9}{y}=\frac{3}{2}

solve for y

y=9(2)/3\\y=6\ lizards

Part C) If the number of snakes in the zoo is increased by 6, how many more lizards would the zoo need to get to keep the same ratio?

Let

x ---> the number of snakes

y ---> the number of lizards

\frac{x}{y}=\frac{3}{2} ----> equation A

For x=6\ snakes

substitute the value of x in the equation A

\frac{6}{y}=\frac{3}{2}

solve for y

y=6(2)/3\\y=4\ lizards

therefore

The zoo would need to get four more lizards to maintain the same proportion

Part D) If the total number of snakes and lizards at the zoo was 20, how many snakes and lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

\frac{x}{y}=\frac{3}{2}

isolate the variable x

x=1.5y ----> equation A

x+y=20 ----> equation B

solve the system by substitution

substitute equation A in equation B

1.5y+y=20

solve for y

2.5y=20

y=8\ lizards

Find the value of x

x=1.5(8)=12\ snakes

therefore

12 snakes and 8 lizards

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