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amm1812
2 years ago
9

2/3 - 1/6 finding the common denominator show me how to do it

Mathematics
1 answer:
Aleksandr [31]2 years ago
5 0
2/3-1/6=4/6-1/6=3/6 simplified is 1/2
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The demand for a daily newspaper at a newsstand at a busy intersection is known to be normally distributed with a mean of 150 an
AURORKA [14]

Answer:

171 newspapers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 150, \sigma = 25

How many newspapers should the newsstand operator order to ensure that he runs short on no more than 20% of days

The number of newspapers must be on the 100-20 = 80th percentile. So this value if X when Z has a pvalue of 0.8. So X when Z = 0.84.

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - 150}{25}

X - 150 = 0.84*25

X = 171

So 171 newspapers.

4 0
3 years ago
Anyone know (Worth lost of points, will mark brainliest!)<br> *I also do not accept links, Sorry!
nadezda [96]
Here ya go! :)
—————-

3 0
2 years ago
Rule:start at 3 1/8 subtract 3/4
SSSSS [86.1K]

Answer:

2 3/8

Step-by-step explanation:

If what you're saying it 3 1/8 - 3/4 then...

3 1/8 - 3/4

3 1/8 - 6/8

25/8 - 6/8

19/8

2 3/8

6 0
3 years ago
Year 1960 1975 1990 2005 2020 (est.) Population P(t) 200,000 240,000 288,000 345,600 414,720 According to the data, what would t
Leno4ka [110]
The correct answer is Choice A) 367,274.

The chart for this data starts in the year 1960. We are looking for the population during year 2010. That is 50 years later.

To find the answer, just input 50 for t in the equation.

P(50) = 200(1.01223)^50
5 0
3 years ago
Use the partial quotient to solve 673÷5
AleksAgata [21]
Our answer would be 134.6
8 0
3 years ago
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