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3 years ago

Describe metallic bonding.

2 answers:

5 0

Metallic bonding is the force of attraction between valence electrons and the metal atoms. Protons in this case act as a glue for many detached electrons and positive ions, giving said substance an actual structure.

tankabanditka [31]3 years ago

4 0

Metallic bonding is the attractive forces between a lattice of positive ions and a sea of delocalized electrons.

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2. Write the charge of each sub-atomic particle in the helium atom above.

algol [13]

Explanation:

The charge of a helium atom is zero

It is neutral because

The number of unit negative charges = number of unit positive charges

One unit negative charge = -1.6 x 10^(-19) which is basically the charge of an electron

One unit positive charge = +1.6 x 10^(-19) which is basically the charge of a proton

A helium atom has 2 protons and 2 electrons, so it is neutral

NOTE: an alpha-particle (He2+) is a charged helium atom it has 2 protons and 0 electrons. Charge of an alpha particle = +3.2 x 10^(-19).

7 0

3 years ago

Substances that contain a transition metal can be oxidizing. The greater the number of oxidation of this metal, the greater the

Ne4ueva [31]

B I think that it but I don’t know

7 0

3 years ago

If an atom, like a metal atom, has fewer valence electrons,

Gre4nikov [31]

Answer:

ionic bonding or covalent

Explanation:

7 0

2 years ago

A sample of argon has a volume of 0.165L at -34.0°C and a 0.98atm of pressure. What would the volume of this gas at STP be?

JulijaS [17]

Answer: 0.185 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.98 atm

$P_2$ = final pressure of gas = 1 atm (at STP)

$V_1$ = initial volume of gas = 0.165 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $-34.0^oC=273-34.0=239.0K$

$T_2$ = final temperature of gas = $273K$ (at STP)

Now put all the given values in the above equation, we get:

$\frac{0.98\times 0.165}{239}=\frac{1\times V_2}{273}$

$V_2=0.185l$

Thus the volume of this gas at STP be 0.185 L

8 0

3 years ago

Isopropyl alcohol is mixed with water to produce a 32.0 % (v/v) alcohol solution. How many milliliters of each component are pre

Sonja [21]

<u>Answer:</u> The volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL

<u>Explanation:</u>

We are given:

32.0 % (v/v) alcohol solution

This means that 32 mL of isopropyl alcohol is present in 100 mL of solution

Volume of water = 100 - 32 = 68 mL

Volume of solution given = 795 mL

Applying unitary method:

In 100 mL of solution, the volume of isopropyl alcohol present is 32 mL

So, in 795 mL of solution, the volume of isopropyl alcohol present will be = $\frac{32}{100}\times 795=254.4mL$

Volume of water in given amount of solution = 795 - 254.4 = 540.6 mL

Hence, the volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL

4 0

4 years ago