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natulia [17]
2 years ago
11

Substances that contain a transition metal can be oxidizing. The greater the number of oxidation of this metal, the greater the

oxidizing character of the substance. In an industrial process in which the use of an oxidizing agent is necessary, only five substances are available: CaO, FeO, Cu₂O, Cr₂O₃ and KMnO₄.
The substance that should be used in this process, as it has a greater oxidizing character, is:


a) Cr₂O₃


b) Cu₂O


c) CaO


d) FeO


e) KMnO₄
Chemistry
1 answer:
Ne4ueva [31]2 years ago
7 0
B I think that it but I don’t know
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Ten lab safety rules
Bogdan [553]
Don't touch your eyes.

Never taste-test unless the teacher tells you to.

Do not touch anything without directions.

Wear safety goggles. 

Wash your hands after each experiment.

Wear proper lab clothes.

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Clean up your workplace.

Act serious; no horseplay!

Report accidents to the teacher right away!


Have a great day, scholar! 
4 0
3 years ago
How many grams of h2 are needed to produce 14.51 g of nh3?
gavmur [86]

Answer:

               2.57 g of H₂

Solution:

The Balance Chemical Equation is as follow,

                                          N₂  +  3 H₂    →    2 NH₃

According to Balance equation,

         34.06 g (2 moles) NH₃ is produced by  =  6.04 g (3 moles) of H₂

So,

               14.51 g of NH₃ will be produced by  =  X g of H₂

Solving for X,

                      X  =  (14.51 g × 6.04 g) ÷ 34.06 g

                     X =  2.57 g of H₂

7 0
3 years ago
Simply parmanent tissue bibliography please help it's for my project ​
daser333 [38]

Answer:

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6 0
2 years ago
At a certain temperature the rate of this reaction is second order in NH4OH with a rate constant of 34.1 M^-1s^-1: Suppose a ves
Tom [10]

Answer:

Time = 0.929s = 0.93s (2 s.f)

Explanation:

Rate constant, k = 34.1 M^-1s^-1

Initial Concentration, [A]o = 0.100M

Time = ?

Final Concentration [A] = 0.0240M

The parameters are represented in the following equation as;

1/[A] = kt + 1/[A]o

kt = 1/[A]  -  1/[A]o

kt = 1/0.0240 - 1/0.1

kt = 31.67

t = 31.67 / 34.1

t = 0.929s = 0.93s (2 s.f)

5 0
3 years ago
How many molecules are in 8.2 moles of CO3
Anarel [89]
I believe the answer is 50.5 molecules 
3 0
3 years ago
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