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slega [8]
3 years ago
12

A sample of argon has a volume of 0.165L at -34.0°C and a 0.98atm of pressure. What would the volume of this gas at STP be?

Chemistry
1 answer:
JulijaS [17]3 years ago
8 0

Answer: 0.185 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.98 atm

P_2 = final pressure of gas = 1 atm  (at STP)

V_1 = initial volume of gas = 0.165 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = -34.0^oC=273-34.0=239.0K

T_2 = final temperature of gas = 273K  (at STP)

Now put all the given values in the above equation, we get:

\frac{0.98\times 0.165}{239}=\frac{1\times V_2}{273}

V_2=0.185l

Thus the volume of this gas at STP be 0.185 L

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