Question

Isopropyl alcohol is mixed with water to produce a 32.0 % (v/v) alcohol solution. How many milliliters of each component are present in 795 mL of this solution

Answer 1

Answer: The volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL

Explanation:

We are given:

32.0 % (v/v) alcohol solution

This means that 32 mL of isopropyl alcohol is present in 100 mL of solution

Volume of water = 100 - 32 = 68 mL

Volume of solution given = 795 mL

Applying unitary method:

In 100 mL of solution, the volume of isopropyl alcohol present is 32 mL

So, in 795 mL of solution, the volume of isopropyl alcohol present will be = $\frac{32}{100}\times 795=254.4mL$

Volume of water in given amount of solution = 795 - 254.4 = 540.6 mL

Hence, the volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL