Massive amounts of energy are contained in an atom's: Select one:

A mixture of methanol and methyl acetate contains 15.0 wt% methanol.

Usimov [2.4K]

The mixture flow rate in lbm/h = 117.65 lbm/h

<h3>Further explanation</h3>

Given

15.0 wt% methanol

The flow rate of the methyl acetate :100 lbm/h

Required

the mixture flow rate in lbm/h

Solution

mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

$\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol$

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

$\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol$

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.

1 kg mixture = 0.85 .methyl acetate

So flow rate for mixture :

$\tt \dfrac{1~kg~mixture}{0.85~methyl~acetat}\times 100~lbm/h=117.65~lbm/h$

5 0

3 years ago

Which of the following molecules has correctly labeled bond dipoles?

Pepsi [2]

The bond dipole moment uses the idea of electric dipole moment to measure the polarity of a chemical bond within a molecule. It occurs whenever there is a separation of positive and negative charges. In the diagram above, option B exhibited a bond dipole moment. I hope this helps.

8 0

3 years ago

PLEASE HELP ME, 20 POINTS

Marrrta [24]

Explanations:

Question 1: Lithium in 20.00+ g is C. or D., but 25.00+ g is D. which means this is the correct option.

I am unsure of Question 2. I don't think it is mole though.

Question 3: Boron in 25.00-30.00 g is B. or D., but 25.00 g would be C.

Question 4: 2.393 x 1024 atoms of Oxygen is 63.58 mole O. I don't know for sure, but I think this is correct.

I am NOT professional. There is a chance I am incorrect. Please reply to me if I've made a mistake.

4 0

3 years ago

Describe the relationship between pure chemistry and applied chemistry

True [87]

Pure chemistry: gain knowledge for own pleasure
Applied chemistry: gain knowledge to know how to use it

7 0

3 years ago

describe how a pure dry sample of solid lead carbonate can be obtained from sodium carbonate solution and lead nitrate solution

djyliett [7]

Answer:

Soluble salts can be made by reacting acids with soluble or insoluble reactants. Titration must be used if the reactants are soluble. Insoluble salts are made by precipitation reactions.

Making insoluble salts

An insoluble salt can be prepared by reacting two suitable solutions together to form a precipitate.

Determining suitable solutions

All nitrates and all sodium salts are soluble. This means a given precipitate XY can be produced by mixing together solutions of:

X nitrate

sodium Y

For example, to prepare a precipitate of calcium carbonate:

X = calcium and Y = carbonate

mix calcium nitrate solution and sodium carbonate solution together

calcium nitrate + sodium carbonate → sodium nitrate + calcium carbonate

Ca(NO3)2(aq) + Na2CO3(aq) → 2NaNO3(aq) + CaCO3(s)

It also works if potassium carbonate solution or ammonium carbonate solution is used instead of sodium carbonate solution. Remember that all common potassium and ammonium salts are soluble.

please mark as brainliest

Explanation:

7 0

3 years ago