First, find out how many grams are in one mole of CO2(the two oxygen atoms means you need to multiply oxygen’s amu by 2,then add whatever carbon’s amu is to that). Then divide 26 grams by that number and that will be your moles. There are only two significant figures, so round your answer correctly.
Explanation:
one mole= 6.02x10^23
Everything going from a mole will always be multiplied and everything going into mole will be divided.
Answer:
8.5gm O2 produced
Explanation:
When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 13.2 g KCl, how many grams of O2 were produced?
for every 2 moles of KCl produced, 3 moles of O2 are produced
Mol weight of KCl =39+35.5=74.5gm
13.2 gm KCl = 13.2/74.5 = 0.177 moles
this will make (3/2) X 0.177 = 0.2655 moles of O2
O2 mol wt is 32 0.2655 X32 = 8.5gm O2 produced
