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Alenkinab [10]
3 years ago
14

the Geography Club is selling wrapping paper for a fundraiser. They ordered 16 cases. If each student in the club takes 2/3 of a

case how many students are in the club
Mathematics
1 answer:
Sever21 [200]3 years ago
6 0

Answer: 24 students are in the club.


Step-by-step explanation: Total number of ordered cases = 16 cases.

Each student in the club takes = 2/3 of a case.

<em>In order to find the number of students for 16 cases, we need to divide 16 2/3rd each.</em>

Therefore,

16 ÷ 2/3

Converting division sign into multiplication and flipping second fraction, we get

16 × 3/2 = 48/2 = 24.

<h3>Therefore, 24 students are in the club.</h3>

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What is the value of k in the equation 5k-2k=12
Mamont248 [21]

Answer:

k =4

Step-by-step explanation:

5k-2k=12

Combine like terms

3k = 12

Divide each side by 3

3k/3 = 12/3

k = 4

5 0
4 years ago
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Answer:

x > - 2

Step-by-step explanation:

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What is the answer to 25÷2760
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3 years ago
A Internet provider has implemented a new process for handling customer complaints. Based on a review of customer complaint data
sergey [27]

Answer:

<em>a)</em><em> The mean time for handling a customer complaint under the new process using 95% confidence level is between 25.0 min. and 27.5 min. </em>

<em>b) </em><em>there is no substantial evidence</em><em> </em><em>(in 95% confidence level) that the new process has reduced the mean time to handle a customer complaint.</em>

<em>c) </em><em>The population about which inferences from these data can be made is the people following the new implemented plan when handling customer complaints.</em>

Step-by-step explanation:

the random sample of the response times of 50 customers who had complaints has

size=50

mean≈26.218

standard deviation ≈4.42

a. Confidence interval can be estimated using the formula:

M±\frac{z*s}{\sqrt{N} } where

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  • z is the corresponding z-score for the 95% confidence interval (1.96)
  • s is the sample standard deviation (4.42)
  • N is the sample size (50)

When we put the numbers in the formula, mean time for handling a customer complain under the new process using 95% confidence interval is:

26.22±\frac{1.96*4.42}{\sqrt{50} }≈ 26.22±1.225 i.e. between 25 and 27.45

b<em>. </em>According to the customer complaint data for the past 2 years, the mean time for handling a customer complaint was 27 minutes. After the plan, estimated mean time for handling customer complaint is between <em>25.0 min. and 27.5 min. with 95% confidence. </em>Since 27 min. is within this interval, we can conclude that there is no substantial evidence (in 95% confidence level) that the new process has reduced the mean time to handle a customer complaint.

c. The population about which inferences from these data can be made is the people following the new implemented plan when handling customer complaints.

5 0
3 years ago
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juin [17]

x _>_ -3

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7 0
4 years ago
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