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4 years ago

5-1+2x(4x4-12)x8 explain

Mathematics

2 answers:

Romashka [77]4 years ago

5 0

First, do what's in the paranthesis:

(4*4-12)

Multiplication first:

16-12

Then subtract:

We get:

5-1+2*4*8

Multiply:

2*4

Multiply, again:

8*8

We get:

5-1+64

Subtract:

5-1

Add:

4+64

Answer: 68

miv72 [106K]4 years ago

3 0

I attached a photo of how to do this.

If you have any further questions feel free to ask.

Hope this helps.

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The tickets in a box are numbered from 1-20 inclusive. If a ticket is chosen at random and replaced, and then a second ticket is

victus00 [196]

1) The sum of the two numbers is even either the two numbers are even or the two numbers are odd.

2) The probability that the two numbers are even is the product of the probabilities for each event:

- Probability that the first number is even: 10 / 20 = 0.5

- Probability that the second number is even: 10 / 20 = 0.5

- Probability that the two numbers are even: 0.5*0.5 = 0.25

3) The probability that the two numbers are odd is the product of the probabilities for each event:

- Probability that the first number is 0dd: 10/20 = 0.5

- Probability that the second number is odd: 10/20 = 0.5

- Probability that both numbers is odd = 0.5*0.5 = 0.25

4) Probability tha the sum is eve: 0.25 + 0.25 = 0.5

Answer: 0.5.

And it is reasonable, half of times the sum is even and half the sum is odd.

4 0

3 years ago

Please help with only the circled ones (1-8)

mixas84 [53]

When you have an exponent divided by another exponent, you subtract the exponents (only when it has the same base)

For example:

$\frac{x^8}{x^3} =x^{8-3}=x^5$

$\frac{x^3}{x^2} =x^{3-2}=x^{1}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive

For example:

$x^{-2}=\frac{1}{x^2}$

$\frac{1}{x^{-5}}=\frac{x^5}{1} = x^5$

$\frac{y^{-2}}{x^{-1}} =\frac{x^1}{y^2} =\frac{x}{y^2}$

1. $\frac{10^{15}}{10^3} =10^{15-3} = 10^{12}$

2. $\frac{(-3)^4}{(-3)^{-3}} =(-3)^{4-(-3)}=(-3)^{4+3} = (-3)^7$

3. $\frac{8}{8^3} =8^{1-3} = 8^{-2}=\frac{1}{8^2}$

4. $\frac{a^{12}}{a^2} =a^{12-2}=a^{10}$

5. $\frac{m^{-2}n^{16}}{m^{4}n^2} =(m^{-2-4})(n^{16-2})=(m^{-6})(n^{14})=\frac{n^{14}}{m^{6}}$

This is one of the ways you could have done it

6. $\frac{p^5q^{-10}}{p^6q^{-2}} =(p^{5-6})(q^{-10-(-2)})=(p^{-1})(q^{-8})=\frac{1}{p^1q^8} =\frac{1}{pq^8}$

7. $\frac{63x^{18}}{9x^{2} }$ Divide 63 and 9

$\frac{7x^{18}}{x^{2}} =(7)(x^{18-2})=(7)(x^{16})=7x^{16}$

8. $\frac{28r^4}{-7r^{15}} =(\frac{28}{-7} )(r^{4-15})=(-4)(r^{-11})=(-4)(\frac{1}{r^{11}} )=\frac{-4}{r^{11}}$

[More information with exponents]

If you multiply an exponent directly with another exponent, you multiply the exponents together

For example:

$(x^{2})^4=x^{2(4)}=x^8$

$(x^{3})^5 =x^{3(5)}=x^{15}$

If you multiply a variable with an exponent by a variable with an exponent, you add the exponents

For example:

$(x^{2}) (x^6)=x^{2+6}=x^8$

$(x^{3})(x^1)=x^{3+1}=x^4$

3 0

3 years ago

a set of angles has a ratio of 5:2 if the larger angle measures 105 degrees then what is the measure of the smaller angle?

Sphinxa [80]

42 degrees. Divide 105 by 5 and get 21 and then multiply it by 2.

7 0

4 years ago

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1. 7p - 6pc + 3c - 2 Number of terms: Coefficients: Constant terms:

Andreas93 [3]

Step-by-step explanation:

Given:

7p - 6pc + 3c - 2

Find:

Number of terms

Coefficients

Constant terms

Computation:

Number of terms = 4

Coefficients = (7, -6, 3)

Constant terms = -2

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3 years ago

A 95% confidence interval estimate for a population mean u is determined to be 75.38 to 86.52. If the confidence level is reduce

PolarNik [594]

Answer:

C. becomes narrower

Step-by-step explanation:

If the confidence level is reduced from 95% to 90%, then, the confidence interval for u becomes narrower, i.e., we are less sure that the true value of u is contained inside the new interval. With a 95% confidence interval there is a probability of 0.95 that the parameter u is inside the interval and with a 90% confidence interval there is a probability of 0.90 that the parameter u is inside the interval.

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3 years ago

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