Answer:
The covalent bond in Cl₂ is break and combine with sodium to form NaCl through ionic bond.
Explanation:
Chemical equation:
Na + Cl₂ → NaCl
Balanced chemical equation:
2Na + Cl₂ → 2NaCl
The given reaction indicate the formation of sodium chloride.
Sodium chloride is an ionic compound. It is formed by the reaction of chlorine and sodium. The type of bond in Cl₂ is covalent. Both chlorine atoms are tightly held together through sharing of electrons. When sodium chloride is formed the covalent between the chlorine atoms are break and it react with sodium . The chlorine toms thus gain the one electron from the sodium atom and became negative ion while sodium by losing its one valance electrons became positive ions. The strong electrostatic forces are develop between them and ionic bond is formed.
Aromatic compounds are compounds that contain carbon-carbon multiple bonds.
The question did not mention that a heteroatom is present in the compound so we can assume that there is none of such. In that case, the compound contains only hydrogen and carbon.
So,
(CH)n = 78
where n is the number of each atom present.
(12 +1)n = 78
n = 78/13
n = 6
The molecular formula of the compound is C6H6
When C6H6 is treated with .conc.HNO3/conc.H2SO4 the compound shown in image 1 is formed. The reaction occurs at the C-C multiple bond.
When C6H6 is reacted with chlorine in the presence of sunlight, hexachlorobenzene (shown in image 2 attached) is formed.
brainly.com/question/24305135
Explanation:
electrons move arround nucleus in the orbit such as sun in suria system..
C. 2
2H_2O + <u>2e</u>^(-) → H_2 + 2OH^(-)
2Cl^(-) → Cl_2 + <u>2e</u>^(-)
2H_2O +Cl^(-) + <u>2e</u>^(-) → H_2 + Cl_2 + 2OH^(-) + 2e^(-)
2H_2O +2Cl^(-) → H_2 + Cl_2 + 2OH^(-)
This is a <em>redox reaction</em> in which two chloride ions transfer two electrons to two molecules of water.
The number of moles hydrogen produced when 6 moles of sodium are used is calculated as below
2Na + 2H2O = 2NaOH +H2
by use of mole ratio between Na to H2 which is 2:1 the moles of H2 is therefore
= 6 x1/2 = 3 moles of H2