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Jet001 [13]
3 years ago
9

Can somebody answer this question for me it might be easy for you answer part 1,2,and 3

Chemistry
2 answers:
jonny [76]3 years ago
8 0

Answer:

hey love! what is the question??

Morgarella [4.7K]3 years ago
3 0
Hi!! Where’s the question?
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I need help with these quickkk WILL GIVE BRAINLIEST PLS
DerKrebs [107]

Answer: number 2

Explanation:

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3 years ago
Please help it's due tomorrow.​
TEA [102]

Answer:

it's to blurry you can't see anything

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3 years ago
Consider the following reaction.
Ivan

Answer:

162 g Fe₂O₃

Explanation:

To find the mass of Fe₂O₃, you need to (1) convert grams C to moles C (via molar mass from periodic table), then (2) convert moles C to moles Fe₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe₂O₃ to grams (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.

Molar Mass (C): 12.011 g/mol

2 Fe₂O₃(s) + 3 C(s) ---> 4 Fe(s) + 3 CO₂(g)

Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (Fe₂O₃): 159.684 g/mol

18.3 g C           1 mole            2 moles Fe₂O₃          159.684 g
--------------  x  ----------------  x  -------------------------  x  -----------------  = 162 g Fe₂O₃
                        12.011 g              3 moles C                 1 mole

5 0
2 years ago
List down two applications of isotopes​
Sidana [21]

Answer:

Give any two application for isotopes

Isotopes of iodine are used for radiotherapy in treatment of hyperthyroidism, cancer, etc.

Uranium, Radium, Polonium isotopes are used in atomic reactors.

Cobalt isotopes are used for irradiation of food products.

5 0
3 years ago
Read 2 more answers
A certain electrolyte solution contains 1 gram of salt for every 8 grams of sugar and every 200 grams of water. If the sugar to
12345 [234]

Answer:

The resulting solution contains approximately 666 g of water.

Explanation:

In the initial solution we have:

1g salt : 8g sugar : 200g water

This means that the ratios are:

\frac{salt}{sugar}  = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}

In the final solution we have:

5g salt: xg sugar: yg water

The new ratios are:

\frac{salt}{sugar} = \frac{3}{8} \\\\\frac{sugar}{water} = \frac{1}{50}

Now we can calculate the amount of sugar in the final solution:

\frac{salt}{sugar}  = \frac{5}{x} =\frac{3}{8} \\\\X = 13.333 g

Finally, we calculate the amount of water:

\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g

4 0
3 years ago
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