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azamat
3 years ago
10

One canned juice drink is 15% orange juice; another is 5% orange juice. How many liters of each should be mixed together in orde

r to get 10L that is 11% orange juice? ...?
Chemistry
1 answer:
Maksim231197 [3]3 years ago
7 0
It uses elimination againLet A be 15% juice and B is 5% juice
A+B = 100.15A + 0.05B = 0.11*10 = 1.1Multiply 2nd equation by 100 to get rid of decimals
A+B = 1015A + 5B = 110
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A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4
balu736 [363]

Answer:

51.53 grams .

Explanation:

Na₃PO₄    ⇄  3Na⁺¹   +    PO₄⁻³ .

1 mole           3 mole

725 mL of 1.3 M Na⁺  ions

= .725 x 1.3 moles of Na⁺ ions

= .9425 moles

3 mole of Na⁺  is formed by 1 mole of Na₃PO₄

.9425 mole of Na⁺  is formed by .9425/3  mole of Na₃PO₄

Na₃PO₄ needed =  .9425/3  moles = .3142 moles

Molecular weight of Na₃PO₄ = 164

grams of Na₃PO₄ needed = .3142 x 164 = 51.53 grams .

8 0
2 years ago
If a substance changes from one phase to another, is it still same substance? why
shutvik [7]
When you boil water, you aren't changing the elements. You're just making water vapor. However, when you burn paper, it becomes carbon (mostly). So physical changes will not change the substance, only chemical changes will.
5 0
2 years ago
What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95
melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

8 0
3 years ago
) Calculating Heat from Thermochemical Equations
SIZIF [17.4K]

A combustion reaction is a reaction that reacts in the presence of oxygen molecules. Methane will release -3115 kJ/mol of heat.

<h3>What is a combustion reaction?</h3>

A combustion reaction includes the reaction between the chemical reactant and oxygen molecule to produce the product. The combustion reaction between methane and oxygen is given as:

CH₄(g) + 2O₂ (g) → CO₂(g) + 2H₂O (l), ΔH = -890 kJ/mol

The stoichiometry coefficient from the reaction gives 1 mole of methane releases -890 kJ/mol enthalpy.

So, 3.5 moles methane will release = 3.5 × -890 = -3115 kJ/mol

Therefore, -3115 kJ/mol of heat is released.

Learn more about combustion reaction here:

brainly.com/question/27823881

#SPJ1

4 0
2 years ago
when Mn2 ions are separated from the mixture, they go through a series of oxidizing and reducing steps. Write the reaction equat
goldfiish [28.3K]

Answer: hello some part of your question is missing below is the missing part

when H₂O and H₂O₂ is added to Mn(OH)₂(s) and put in water bath to dissolve

answer : attached below

Explanation:

When Mn²⁺ ions are separated from the mixture, attached below are the requires reaction equations that shows the process of separation.

Mn²⁺ ions are separated to the right of the reaction  equations

8 0
3 years ago
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