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lilavasa [31]
3 years ago
11

) determine the henry's law constant for ammonia in water at 25°c if an ammonia pressure of 0.022 atm produces a solution with a

concentration of 1.3 m.
a.59 m/atm

b.0.029 m/atm

c.0.038 m/atm

d.35 m/atm

e.0.017 m/atm
Chemistry
1 answer:
Nataly [62]3 years ago
3 0

Answer:

a. 59 m/atm

Explanation:

  • To solve this problem, we must mention Henry's law.
  • <em>Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.</em>
  • It can be expressed as: C = KP,

C is the concentration of the solution (C = 1.3 M).

P is the partial pressure of the gas above the solution (P = 0.022 atm).

K is the Henry's law constant (K = ??? M/atm),

∵ C = KP.

∴ K = C/P = (1.3 M)/(0.022 atm) = 59.0 M/atm.

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What is the reactant(s) in the chemical equation below?
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Explanation:

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7 0
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Answer:

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As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

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3 0
3 years ago
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