All categories

4 years ago

Please help ASAP :,(

Mathematics

1 answer:

Stells [14]4 years ago

4 0

Answer:

110

Step-by-step explanation:

You might be interested in

Vincent's pie recipe calls for 5 ounces of pecans and 7 ounces of walnuts. How many total ounces of nuts does his recipe call fo

sergij07 [2.7K]

Answer:

12 nuts

Step-by-step explanation:

$7 + 5 = 12$

4 0

3 years ago

I I need help with this I’ll mark you if your right

AveGali [126]

Answer:

Step-by-step explanation:

The distance around the circle is asking for the circumference of the circle.

Since we know that the diameter is 21 and the equation for the circumference of a circle is 2*pi*r and since 2*r is just the diameter, we can say that the circumference is 21*pi, which would be C.

8 0

3 years ago

Read 2 more answers

19. Use the unit circle to find the value of tan 315º.<br> Show work pls.

Free_Kalibri [48]

Answer: -1

Step-by-step explanation:

First change tan(315) to:

$\frac{\sin(315)}{\cos(315)}$

Then evaluate the sine and cosine function. What is the y component of 315 degrees? What is the x component of 315 degrees?

$-\frac{\sqrt{2} }{2} /\frac{\sqrt{2} }{2} =-1$

7 0

3 years ago

He CEO of Hot Tires compares factory production for his two factories using the data in the table shown below.

zhenek [66]

Answer: A factory b is produced more tired than Factory A because factory B has a median of 112 and factory A has a median of 102.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=y%2B%20%20%5Cfrac%7B13%7D%7B4%7D%20%20%3D%20%28x%5E2-%20%5Cfrac%7B1%7D%7B2%7D%20%29%5E2" id="T

zhenek [66]

Answer: $\bold{y=\dfrac{1\pm \sqrt{4x+13}}{2}}$

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and solve for y:

$y+\dfrac{13}{4}=\bigg(x-\dfrac{1}{2}\bigg)^2\\\\\\x+\dfrac{13}{4}=\bigg(y-\dfrac{1}{2}\bigg)^2\rightarrow \text{(swapped the x's and y's)}\\\\\\\sqrt{x+\dfrac{13}{4}}=\sqrt{\bigg(y-\dfrac{1}{2}\bigg)^2}\rightarrow \text{(took square root of both sides)}\\\\\\\sqrt{\dfrac{4x+13}{4}}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(created common denominator in radical)}\\\\\\ \dfrac{\sqrt{4x+13}}{2}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(simplified radical)}$

$\pm \dfrac{\sqrt{4x+13}}{2}=y-\dfrac{1}{2}}\rightarrow \text{(divided both sides by}\ \pm )\\\\\\\dfrac{1}{2}\pm \dfrac{\sqrt{4x+13}}{2}=y\quad \rightarrow \text{(added}\ \dfrac{1}{2}\ \text{to both sides)}\\\\\\\dfrac{1\pm \sqrt{4x+13}}{2}=y\quad \rightarrow \text{(combined numerators)}$

4 0

3 years ago