the square root of 121, because when rationalized its 11.
Answer:
Find a polynomial function whose graph passes through (6,13), (9,-11), (0,5)
1 Answers
Assuming a quadratic, we have that
y = ax^2 + bx + c
Since (0,5) is on the graph, c =5
And we have the remaining system
a(9)^2 + b(9) + 5 = -11
a(6)^2 + b(6) + 5 = 13 simplify
81a + 9b = -16 multiply through by 6 ⇒ 486a + 54b = - 96 (1)
36a + 6b = 8 multiply through by -9 ⇒ -324a -54b = -72 (2)
Add (1) and (2)
162a = -168
a = -28/27
To find b we have
36 (-28/27) + 6b = 8
-112/3 + 6b = 8
⇒ b = 68/9
The function is
y = - (28/27)x^2 + (68/9)x + 5
Answer:
1/2 of an answer is zero answer.
Answer(s):
For question one, I believe it would be False.
For question two, It will be the <u>Amount of payment.</u>
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Answer:
x=6
Step-by-step explanation:
x+1
-------
x-6
The expression is undefined when the denominator is zero
x-6 =0
Solving for x
x+6-6 =0+6
x=6
