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musickatia [10]
3 years ago
6

To two decimal places, what is the relative

Chemistry
1 answer:
Dmitrij [34]3 years ago
3 0

Answer:

The atomic mass of Potassium is 39.09 u+-0.0001u and molar mass is  39.09 g,s/mole

Explanation:

Potassium is a metal belongs to group 1 and period 4 whose atomic number is 19 and electron configuration is 2,8,8,1.

The molar mass of Potassium or K is 39.09 g,s/mole and the atomic mass is 39.09 u+-0.0001u. Potassium was first discovered by Humphrey Davey and was first found in the ashes of plants. It also occurs in the mineral sylvite or KCL and is mined as such.

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Some plz help me make mnemonic to helpme remember the oder of the planets​
Iteru [2.4K]

Answer:

My - Mercury

Very- Venus

Excited- Earth

Mother- Mars

Just- Jupiter

Served- Saturn

Us- Uranus

Nachos- Neptune

Explanation:

Mark me Brainliest?

3 0
3 years ago
Read 2 more answers
Draw the products of the complete hydrolysis of an acetal. Draw all products of the reaction.
jolli1 [7]

Answer: the product is ketone or aldehyde

Explanation:

The first step is the conversion of acetal to hemiacetal in the presence of H3O+/ ROH, and then the final conversion of hemiacetal to ketone/aldehyde using

H3O+/ ROH...

Attached is the structural conversion

8 0
4 years ago
List the protons, neutrons, and electrons for Ge2+<br> Please hurry
Nady [450]

Answer:

32, 30 and 41

Explanation:

The problem here is to find the number of:

    Protons, neutrons and electrons in Ge²⁺

In this ion,

   We must understand that for a net positive charge to remain on an atom, the number of protons must be greater than the number of electrons.

Ge is Germanium with atomic number of 32;

So the number of protons is 32

Since the atom has lost two electrons;

  Number of electrons now is 32  - 2 = 30

Number of neutrons is 41 from the periodic table.

7 0
3 years ago
Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.
Vsevolod [243]

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

<h3>Balanced equation </h3>

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₃PO₄ (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 3

<h3>How to determine the volume of Ca(OH)₂ </h3>
  • Molarity of acid, H₃PO₄ (Ma) = 0.390 M
  • Volume of acid, H₃PO₄ (Va) = 24.5 mL
  • Molarity of base, Ca(OH)₂ (Mb) = 0.279 M
  • Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

Learn more about titration:

brainly.com/question/14356286

5 0
2 years ago
An object has a mass of 55 grams and a density of 3.23g/ml ? what is the volume
lara [203]
Volume= mass divided by density
V= m/d
55/3.23
= 17.03
8 0
3 years ago
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