Answer:
-3.617 °C
Explanation:
Step 1: Given data
Mass of water (m): 210.0 g
Energy released in the form of heat (Q): -3178 J (the minus sign corresponds to energy being released)
Specific heat of water (c): 4.184 J/g.°C
Temperature change (ΔT): ?
Step 2: Calculate the temperature change
We will use the following expression.
Q = c × m × ΔT
-3178 J = 4.184 J/g.°C × 210.0 g × ΔT
ΔT = -3.617 °C
The answer is B
To write the equilibrium constant for an equation, all you have to do is divide the products by the reactants. The reactants are always on the left side, and the products are always on the right side. The coefficients of the elements will be written as the exponent of that same element. However, in this equation, we do not have to write any exponents, as there are no coefficient but 1.
Answer:
41.16 moles of H2O
Explanation:
Ratio for the products-reactants is 1:6, so 1 mol of glucose is produced when plants use 6 moles of water.
Then, let's make a rule of three:
1 mol of glucose is produce by using 6 moles of water
6.86 moles of glucose are produced by the use of (6 . 6.86)/1 = 41.16 moles of H2O
Answer:
D. cis-2-pentene (looks like a frying pan)
Explanation:
pentane looks lihe the letter M
2-methylpentane looks like YV
2-pentyne looks like an upside down L
