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Readme [11.4K]
2 years ago
13

Prove that: –7 is not the arithmetic square root of 49

Mathematics
1 answer:
frez [133]2 years ago
6 0

Answer:

–7 is not the arithmetic square root of 49 only in case we are taking it for natural number.

Step-by-step explanation:

  • The square root of x is that number which on squaring gives the result as x.
  • For example, the square root of 4 is +2 or -2. Because on squaring +2 or -2 we get the number 4.
  • Similarly for the case of 49, the square root might be both +7 or -7.
  • But if we are taking it as a natural number then -7 is not valid. Like for length, quantity or other sort of things -7  is not the arithmetic square root of 49.
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Can you guys please help me with 3 and 4 I really need help I will give you 14 points
AURORKA [14]
For answer #3...
just replace (T) with 76.50 in the equation T=9h
Then since this is a division problem you would do 76.50/9=9h/9
This gives you your answer which is h=8.5.
Hope this helps!!:)
6 0
3 years ago
The price of a TV rose from $350 to $371 in one<br> month. By what percent did the TV price rise?
lesantik [10]
6% increase


To calculate the percentage increase:
First: work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number

Then: divide the increase by the original number and multiply the answer by 100.

% increase = Increase ÷ Original Number × 100.

If your answer is a negative number, then this is a percentage decrease.
4 0
3 years ago
“3 less than the quotient of y and 4”
Bingel [31]

Answer:

Expression:

\dfrac{y}{4}-3

Value where y = 20

2

Step-by-step explanation:

Let's take a look at the sentence:

3 less than the quotient of y and 4

3 less indicates that you will subtract

   - 3

Quotient means the result of division.

\dfrac{y}{4}

So if we combine the two, it says 3 less than the quotient so we subtract 3 from the quotient:

\dfrac{y}{4}-3

So if y = 20, we just substitute the y with 20

\dfrac{y}{4}-3

\dfrac{20}{4}-3

5-3=2

8 0
3 years ago
Find the square. (1/4A + 1/4B)^2<br><br> a) 1/16A^2 + 1/8AB + 1/16B^2<br> b) 1/4A^2 + 1/8AB + 1/4B^2
alisha [4.7K]

(a + b)^2 = a^2 + 2ab + b^2

(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =

= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B^2

Answer: A.

Another way to solve by factoring 1/4.

(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =

= [\dfrac{1}{4}(A + B)]^2

= (\dfrac{1}{4})^2(A + B)^2

= \dfrac{1}{16}(A^2 + 2AB + B^2)

= \dfrac{1}{16}A^2 + \dfrac{1}{16}2AB + \dfrac{1}{16}B)^2

= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B)^2

6 0
3 years ago
Read 2 more answers
Which gives the correct values for points A, B, C, and D?
beks73 [17]

Answer:

The correct answer for this problem is the 2nd one because all you have to do is count how far each one is from -1 and -2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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