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Molodets [167]
3 years ago
10

PLs HELP me with this question I really need it!!!!!!

Mathematics
2 answers:
melisa1 [442]3 years ago
7 0

Answer:

A.the radius

Step-by-step explanation:

The area of a sector of a circle is ½ r² ∅, where r is the radius and ∅ the angle in radians subtended by the arc at the centre of the circle. So in the below diagram, the shaded area is equal to ½ r² ∅ .

plz mark me as brainliest :)

DaniilM [7]3 years ago
3 0

Answer:the radius

Step-by-step explanation:

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Simplify the product using FOIL. (3x + 4)(2x – 6)
Arturiano [62]

Answer:

6x^2 - 10x - 24

Step-by-step explanation:

  1. Do 3x times 2x which is 6x^2
  2. Do 3x times - 6 which is -18x
  3. Do 4 times 2x which is 8x
  4. Do 4 times - 6 which is - 24
  5. You get 6x^2 - 18x + 8x - 24
  6. Simplyify to get the answer
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4 years ago
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Answer:

1681 for area of <em>rectangle</em>

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3 years ago
Give two different methods you could use to put the fractions 1/2, 3/4, 3/8, 5/8, 5/16, 7/16, 9/16, and 11/16 in order
alina1380 [7]
You could give all of the fractions a common denominator. You could also solve each of them (1/2=0.5) to see their value and order them through the value.
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3 years ago
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
Please Help!!!!! Extra points and brainiest will be given!!!!!
Orlov [11]

Answer:

the big tank can hold 2027.37 m³of water

10 small tanks can be filled

Step-by-step explanation:

r = 11, h = 16

V = (1/3)πr²h

V = (1/3)121π(16)

1936π/3 = 2027.37

2027.37/200 = 10. 136

10 tanks

8 0
3 years ago
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