Answer:
A. 76
B. We will get two real solutions for the equation.
Step-by-step explanation:
A
For any quadratic equation ax²+bx+c=0, the discriminant is b²-4ac.
In 3x²-2x-6=0, a=3, b=-2 and c=-6:
b²-4ac
(-2)²-4(3)(-6)=4+72=76
B.
When the discriminate is positive we get two real solutions to the equation, when it's zero we get one real solution, and when it's negative we get two complex solutions. Since our discriminate, 76, is positive, we know that we will get two real solutions to 3x²-6=2x.
4x+3x=42
7x=42
x=6
4(6)+3(6)=42
24+18= 42
42=42
I know it's too much but hope this helped :)
Answer:
13c+10d>150
Step-by-step explanation:
Answer:
−1 ≤ n + 7 < 9
To solve a compound inequality separate it into two inequalities
That is
n + 7 ≥ - 1 and
n + 7 < 9
Solve the inequality
n + 7 ≥ -1
n ≥ - 8
and
n + 7 < 9
n < 7 - 9
n < 2
Find the intersection
The final answer is
-8 ≤ n < 2
Hope this helps
