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Leto [7]
3 years ago
12

Five-card poker hand is dealt at random from a standard 52-card deck.

Mathematics
1 answer:
Alisiya [41]3 years ago
5 0

Answer:

Step-by-step explanation:

a) The probability that the hand contains exactly one ace

No of ways of selecting one ace and four non ace would be

=4C1 (48C4)\\\\= 778320

i.e. α=778320

b) the probability that the hand is a flush

No of ways of getting a flush is either all 5 hearts or clubs of spades or dice

= 4(13C5) = 5148

ie. β=5148

c)  the probability that the hand is a straight flush

In each of the suit to get a straight flush we must have either A,2,3,4,5 or 2,3,4,5,6, or .... or 9,10, J, q, K

So total no of ways = =9(13C5) 4\\= 46332

γ=46332

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Solve the equation.<br><br> 5d = 17.1<br><br><br> 12.1<br><br> 22.1<br><br> 85.5<br><br> 3.42
Rudiy27

Hello there!


5d = 17.1

The equation is asking you to find the value for "d". How to do that? Well, all you have to do is divide both side by 5.

5d/5 = 17.1

d = 3.42  

That's your answer!


You can even double check your work, if you want to. How? Well, you just need to replace 3.42 where it belongs.

5(3.42) = 17.1

17.1 = 17.1

True!


Let me know if you have additional questions. As always, it is my pleasure to help students like you!

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