Question

Five-card poker hand is dealt at random from a standard 52-card deck.

Answer 1

Answer:

Step-by-step explanation:

a) The probability that the hand contains exactly one ace

No of ways of selecting one ace and four non ace would be

=$4C1 (48C4)\\\\= 778320$

i.e. α=778320

b) the probability that the hand is a flush

No of ways of getting a flush is either all 5 hearts or clubs of spades or dice

= $4(13C5) = 5148$

ie. β=5148

c)  the probability that the hand is a straight flush

In each of the suit to get a straight flush we must have either A,2,3,4,5 or 2,3,4,5,6, or .... or 9,10, J, q, K

So total no of ways = $=9(13C5) 4\\= 46332$

γ=46332