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kari74 [83]
3 years ago
6

The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m

ean of 0.018 failures per hour. (a) What is the probability that the instrument does not fail in an 8-hour shift? (b) What is the probability of at least 1 failure in a 24-hour day? Round your answers to four decimal places (e.g. 98.7654).
Mathematics
1 answer:
Mazyrski [523]3 years ago
3 0

Answer:

The probability that the instrument does not fail in an 8-hour shift is P(X=0) \approx 0.8659

The probability of at least 1 failure in a 24-hour day is P(X\geq 1 )\approx 0.3508

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

P(X)=\frac{e^{-\mu}\mu^x}{x!}

Let X be the number of failures of a testing instrument.

We know that the mean \mu = 0.018 failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is \mu=8\cdot 0.018=0.144

P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is \mu=24\cdot 0.018=0.432

P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508

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The population of the world was 7.1 billion in 2013, and the observed relative growth rate was 1.1% per year. A) Estimate how lo
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Answer:

A) 63.36 years.

B) 100.42 years.

Step-by-step explanation:

We have been given that the population of the world was 7.1 billion in 2013, and the observed relative growth rate was 1.1% per year.

A) Since we know that population increases exponentially, therefore we will use our given information to form an exponential model for population increase and then we will solve for the time by which our population will be double.

P(t)=7.1(1.011)^{t}            

7.1 \times 2=7.1(1.011)^{t}  

\frac{7.1 \times 2}{7.1} =(1.011)^{t}

2 =(1.011)^{t}

Now let us solve for t using logarithm.

ln(2) =ln (1.011)^{t}      

ln(2) =t \cdot ln(1.011)

0.6931471805599453 =t \cdot 0.0109399400383344  

t=\frac{0.6931471805599453}{0.0109399400383344}

t=63.3593217267282743049\approx 63.36

Therefore, it will take 63.36 years the population to be double.

B) Now we will find the number of years it will take the population to be triple of its size.

7.1 \times 3=7.1(1.011)^{t}

\frac{7.1 \times 3}{7.1} =(1.011)^{t}  

3 =(1.011)^{t}

Now let us solve for t using logarithm.        

ln(3) =ln (1.011)^{t}

ln(3) =t \cdot ln(1.011)

1.0986122886681097 =t \cdot 0.0109399400383344  

t=\frac{1.0986122886681097}{0.0109399400383344}

t=100.4221490079915311298\approx 100.42

Therefore, it will take 100.42 years the population to triple of its size.


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12) 4x- y=8

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Answer:

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Step-by-step explanation:

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