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Sergio [31]
2 years ago
5

4/5 x 3 x ½ = I need this to pass, thanks.

Mathematics
2 answers:
dsp732 years ago
4 0

Answer:

4/5 x 3 x ½ = \frac{6}{5} or 1\frac{1}{5}

Step-by-step explanation:

You can set up your given question by transforming all of the numbers into fraction:

\frac{4}{5} *\frac{3}{1} *\frac{1}{2}

Then, you can multiply the numerators together, and the denominators:

\frac{4*3*1}{5*1*2}  = \frac{12}{10}

Reducing \frac{12}{10} down to lowest terms will give you: \frac{12}{10}  ÷  \frac{2}{2} =  \frac{6}{5} or 1\frac{1}{5}

Y_Kistochka [10]2 years ago
3 0

Answer:

i hope this helps , mark me brainlist

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Jamal wants to find the sum of 6/10 and 17/100. He says the sum is twenty-three hundreths. What was his mistake?
Veseljchak [2.6K]
His mistake is he didn't make 6/10 to 60/100 he added them without changing the 6/10
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3 years ago
What is a division sign beside ‘/‘?
Andrew [12]

Answer:

Division can be represented with ÷ as well.

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2 years ago
A bag contains 4 white,5 blacks and 2 blue balls. 3 balls are drawn one after the other without replacement from the bag .what i
Doss [256]

Answer:

24/99

Step-by-step explanation:

From the question given above, the following data were obtained:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

Probability that they are of different color =?

Next, we shall determine the total number of balls in the bag. This can be obtained as follow:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 4 + 5 + 2 = 11 balls

Next, we shall determine the possible outcome of draw. This can be obtained as follow.

The possible outcome could be:

WBLB or WBBL or BBLW or BWBL or BLBW or BLWB

Next we shall determine the probability of each of outcomes.

Since the ball is drawn without replacement, it means the total number of ball will reduce after each draw.

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 11

P(WBLB) = 4/11 × 2/10 × 5/9 = 40/990

P(WBLB) = 4/99

P(WBBL) = 4/11 × 5/10 × 2/9 = 40/990

P(WBBL) = 4/99

P(BBLW) = 5/11 × 2/10 × 4/9 = 40/990

P(BBLW) = 4/99

P(BWBL) = 5/11 × 4/10 × 2/9 = 40/990

P(BWBL) = 4/99

P(BLBW) = 2/11 × 5/10 × 4/9 = 40/990

P(BLBW) = 4/99

P(BLWB) = 2/11 × 4/10 × 5/9 = 40/990

P(BLWB) = 4/99

Finally, we shall determine the probability that they are of different color. This can be obtained as follow:

P(WBLB) = 4/99

P(WBBL) = 4/99

P(BBLW) = 4/99

P(BWBL) = 4/99

P(BLBW) = 4/99

P(BLWB) = 4/99

Probability that they are of different color =?

Probability that they are of different color = P(WBLB) + P(WBBL) + P(BBLW) + P(BWBL) + P(BLBW) + P(BLWB)

= 4/99 + 4/99 + 4/99 + 4/99 + 4/99 + 4/99

= (4 + 4 + 4 + 4 + 4 + 4)/99

= 24/99

Thus, the probability that they are of different color is 24/99

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3 years ago
Write a function rule that represents the situation.
NemiM [27]

Answer:

6.50+0.70t

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

12*100=1200/48=25

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