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4 years ago

Which noble gas has the same electron configuration as the oxygen in a water molecule?

Chemistry

1 answer:

OverLord2011 [107]4 years ago

5 0

Neon is a noble gas and has the same noble gas as an oxygen in a water molecule.

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If two substances combine to form a new substance with different properties, a __________ change has occurred.

Ket [755]

Explanation:

When two substances chemically combine together then it results in the formation of a new compound whose chemical properties are different from the reactant species.

Thus, there will be change in the chemical composition when reactants combine together.

Therefore, we can conclude that if two substances combine to form a new substance with different properties, a chemical change has occurred.

6 0

3 years ago

Read 2 more answers

A fat is composed, in part, of long chains of carbon and hydrogen. This fat as a molecular

IgorLugansk [536]

Answer:

$C_{54}H_{102}O_6$

Explanation:

Hello!

In this case, since the molar mass of the empirical formula is:

$MM_{empircal}=9*12.01+17*1.01+16.00=141.26g/mol$

Thus, the ratio of the molecular to the empirical formula is:

$\frac{847g/mol}{141.26g/mol} =6.0$

Thus, the molecular formula is six times the empirical formula:

$C_{54}H_{102}O_6$

Best regards!

8 0

3 years ago

Examine the false statement.

Fynjy0 [20]

The alkali earth metals have two valence electrons.
Hope this helps! :)

5 0

4 years ago

Read 2 more answers

Match the layers of the atmosphere

Ira Lisetskai [31]

Answer:

What language is this please i need help

7 0

3 years ago

A thin-walled sphere rolls along the floor. What is the ratio of its translational kinetic energy to its rotational kinetic ener

ICE Princess25 [194]

Explanation:

The kinetic energy of translation

$E_1=\frac{1}{2}mv^2$

m= mass v= linear velocity

The kinetic energy of rotation

$E_2=\frac{1}{2}I\omega^2$

I= MOI of the thin walled sphere =kmR^2

where ω= v/R= angular velocity

$E_2=\frac{1}{2}kmR^2\frac{v}{R}^2$

Then

$\frac{E_1}{E_2} = \frac{0.5mv^2}{0.5kmR^2\frac{v}{R}^2 }$

=1/k

solid sphere: k=0.4; E1/E2 =1/0.4 = 2.5;

hollow sphere: k=2/3; E1/E2 = 1.5

3 0

3 years ago