Answer:
The equilibrium constant for CO now
= 0.212 M
For H₂O
= 0.212 M
For CO₂ = x = 0.2880 M
For H₂ = x = 0.2880 M
Explanation:
The chemical equation for the reaction is:
CO(g) + H2O(g) ⇌ CO2(g) + H2(g)
The ICE Table for this reaction can be represented as follows:
CO(g) + H2O(g) ⇌ CO2(g) + H2(g)
Initial 0.5 0.5 - -
Change -x -x + x + x
Equilibrium 0.5 -x 0.5 - x
The equilibrium constant![K_c = \dfrac{[x][x]}{[0.5-x][0.5-x]}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cdfrac%7B%5Bx%5D%5Bx%5D%7D%7B%5B0.5-x%5D%5B0.5-x%5D%7D)
![K_c = \dfrac{[x]^2}{[0.5-x]^2}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cdfrac%7B%5Bx%5D%5E2%7D%7B%5B0.5-x%5D%5E2%7D)
where; 



1.3583 (0.5-x) = x
0.67915 - 1.3583x = x
0.67915 = x + 1.3583x
0.67915 = 2.3583x
x = 0.67915/2.3583
x = 0.2880
The equilibrium constant for CO now = 0.5 - x
= 0.5 - 0.2880
= 0.212 M
For H₂O = 0.5 - x
= 0.5 - 0.2880
= 0.212 M
For CO₂ = x = 0.2880 M
For H₂ = x = 0.2880 M
<u>Answer:</u> The change in temperature is 84.7°C
<u>Explanation:</u>
To calculate the change in temperature, we use the equation:

where,
q = heat absorbed = 1 kCal = 1000 Cal (Conversion factor: 1 kCal = 1000 Cal)
m = mass of steel = 100 g
c = specific heat capacity of steel = 0.118 Cal/g.°C
= change in temperature = ?
Putting values in above equation, we get:

Hence, the change in temperature is 84.7°C
Among all of the choices listed, the only option that is a base would be the last one. As it is unique, whereby Hydrogen is not present in the front of the compound.
Bases also possess OH in their molecular formula.