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ElenaW [278]
3 years ago
14

Can someone help me with this

Chemistry
2 answers:
topjm [15]3 years ago
8 0

Answer: It would be malleable, solids, luster, conductors, reactive

Explanation:

Sedbober [7]3 years ago
5 0

Answer:

D

Explanation:

Please give me brainliest :)

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Same amount of mass. 
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The element chlorine is represented by the symbol ____. (Capitalization is important.)
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bromine is a liquid at a room temperature. the volume of the sample of bromine is measured in a 50 mL beaker and a 100 mL beaker
Anna007 [38]

Answer:

This question is incomplete

Explanation:

This question is incomplete but generally it seem to test the knowledge of accuracy. Accuracy is the closeness of a measured value to the specific or actual value of the substance being measured. Hence, the smaller the entire scale that can contain all the substance being measured, the higher the possibility of accuracy to be achieved. For example, a pen of 10.4 cm in length can be better/accurately measured (length) with a 30 cm meter rule than a 1 m  meter rule.

From the question, the 50 mL beaker will provide a "more accurate" measurement of the volume of the bromine than the 100 mL beaker if the 50 mL beaker can contain all the sample of bromine water provided.

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3 years ago
Determine the ΔH for the following reaction 2NH3 + 5/2O2 = 2NO(g) + 3 H2O(g)
beks73 [17]

The enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

<h3>What is enthalpy change, ΔH, of a reaction?</h3>

The enthalpy change of a reaction is the heat changes that occurs when a reaction proceeds to formation of products.

  • Enthalpy change, ΔH = ΔH of products - ΔH of reactants

The equation of the reaction is given below

2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g)

\Delta{H_{f}\:of\:NO = 90.25 kJ; \Delta{H_{f}\:of\:H_{2}O =-241.82kJ;  \Delta{H_{f}\:of\:NH_{3} =-46.1 kJ;  \Delta{H_{f}\:of\:O_{2} =0

\Delta{H_{f}\:of\:rxn = (90.25*2)+(-241.82*3)-( -46.1*2)= -452.76\:kJ

Therefore, the enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

Learn more about enthalpy change at: brainly.com/question/14047927

#SPJ1

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