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Marina86 [1]
4 years ago
9

If a horse is moving and then come to a stop is the horse accelerating or decelerating

Chemistry
2 answers:
quester [9]4 years ago
7 0

Answer:

decelerating hope this helps❤️

OleMash [197]4 years ago
3 0

Answer:

Decelerating

Explanation:

It is slowing down, not speeding up.

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In the kinetic theory the particles in a gas behavior:_____.
Ulleksa [173]

Answer:

In the kinetic theory the particles in a gas behavior are constant and in linear motion

Explanation:

8 0
4 years ago
How to go from a compound to a name and from a name to a compound?
Leno4ka [110]
Convert between the chemical formula of an ionic compound and its name ... When naming ionic compounds, the cation retains the same name as the element.
6 0
3 years ago
The pressure of a sample of ch4 gas (6.022 g) in a 30.0 l vessel at 402 k is __________ atm
mel-nik [20]
From  ideal  gas  equation,  that  is   PV =nRT
P=nRT/V
n  is  the  number  of  moles
the molar  mass  of  CH4 =12+4=16
R  is the gas  contant (0.0821 atm/mol/k)
n= 6.022/16=0.376 moles
P={(0.376 moles  x 0.0821 atm/mol/k  x 402k) /30.0L} =0.414 atm
4 0
3 years ago
Read 2 more answers
HELP QUICK!!!
madreJ [45]

Answer:

The 150 g Al will reach a higher temperature.

Explanation:

  • The amount of heat added to a substance (Q) can be calculated from the relation:

Q = m.c.ΔT.

where, Q is the amount of heat added,

m is the mass of the substance,

c is the specific heat of the substance,

ΔT is the temperature difference (final T - initial T).

<em>Since, Q and c is constant, ΔT will depend only on the mass of the substance (m).</em>

∵ ΔT is inversely proportional to the mass of the substance.

∴ The piece with the lowest mass (150.0 g) will reach a higher temperature than that of a higher mass (250.0 g).

<em>So, the right choice is</em>: The 150 g Al will reach a higher temperature.

5 0
3 years ago
How many grams of Cl2 must react to produce 0.0923 mol of AlCl3? Show work.
alexandr402 [8]

First, let's state the chemical reaction:

2Al+3Cl_2\to2AlCl_3\text{.}

We can find the number of moles of Cl2 required to produce 0.0923 moles of AlCl3, doing a rule of three: 3 moles of Cl2 reacted produces 2 moles of AlCl3:

\begin{gathered} 3molesCl_2\to2molesAlCl_3 \\ \text{?moles Cl}_2\to0.0923\text{ moles }AlCl_3\text{.} \end{gathered}

The calculation would be:

0.0923molesAlCl_3\cdot\frac{3molesCl_2}{2molesAlCl_3}=0.138molesCl_2.

And the final step is to convert this number of moles to grams. Remember that the molar mass can be calculated using the periodic table, so the molar mass of Cl2 is 70.8 g/mol, and the conversion is:

0.138molesCl_2\cdot\frac{70.8gCl_2}{1molCl_2}=9.770gCl_2.

The answer is that we need 9.770 grams of Cl2 to produce 0.0923 moles of AlCl3.

3 0
1 year ago
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