Answer:
33.7 kg
Explanation:
Let's consider calcium phosphate Ca₃(PO₄)₂.
The molar mass of Ca₃(PO₄)₂ is 310.18 g/mol and the molar mass of P is 30.97 g/mol. In 1 mole of Ca₃(PO₄)₂ (310.18 g) there are 2 × 30.97 g = 61.94 g of P. The mass of Ca₃(PO₄)₂ that contains 3.57 kg (3.57 × 10³ g) of P is:
3.57 × 10³ g × (310.18 g Ca₃(PO₄)₂/61.94 g P) = 1.79 × 10⁴ g Ca₃(PO₄)₂
A particular ore contains 53.1% calcium phosphate. The mass of the ore that contains 1.79 × 10⁴ g of Ca₃(PO₄)₂ is:
1.79 × 10⁴ g Ca₃(PO₄)₂ × (100 g Ore/ 53.1 g Ca₃(PO₄)₂) = 3.37 × 10⁴ g Ore = 33.7 kg Ore
To balance equations you have to have same number of atoms on both sides of the equation just multiply with a suitable digit
Answer:
Heat lost would be 606.375J
Explanation:
Mass = 63.0g
T1 = 48°C
T2 = 23°C
Specific heat capacity of copper (c) = 0.385J/g°C
Q = Mc∇T
Q = Mc(T₂ - T₁)
Q = 63 * 0.385 * (23 - 48)
Q = 24.255 * -25
Q = -606.375J
The heat lost would be 606.375J
Answer:
its atomic number will be 3 and it's mass number will be 7. it is lithium
