3.5 moles of ammonia (NH₃) are produced
Explanation:
We have the following chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):
3 H₂ + N₂ → 2 NH₃
number of moles = mass / molecular weight
number of moles of N₂ = 48.97 / 28 = 1.75 moles
We see from the chemical reaction that 1 mole of N₂ will react with 3 moles of H₂, so 1.75 moles of nitrogen will react with 3 × 1.75 = 5.25 moles of H₂. We have 7.32 moles of H₂, a quantity more of what is needed, so the limiting reactant is N₂.
Knowing this we devise the following reasoning:
if 1 mole of N₂ produces 2 moles of NH₃
then 1.75 moles of N₂ produces X moles of NH₃
X = (1.75 × 2) / 1 = 3.5 moles of NH₃
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limiting reactant
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A.fluoride
Fluoride helps to prevent tooth decay
Answer:
A mole is the amount of pure substance containing the same number of chemical units as there are atoms in exactly
12 grams of carbon-12 (i.e., 6.023 X 1023).
Explanation:
Answer:
Option A=> -NHCOCH3 and option C = -CH3.
Explanation:
The option A that is -NHCOCH3 is CORRECT because it possesses lone pair of electron with the exception of group 7A elements. It is this lone pair that is used in the Activation of the ring towards substitution. Other groups that falls into this group are; OCH3, alkyls and many others.
Option B that is -COOH is good group for withdrawal of electron through Resonance. Other examples are NO2, -CN and SO3H.
Option C falls to the same category as option A above that is Activation of the ring towards substitution.
Option D falls to the same category as option B above that is group for withdrawal of electron through Resonance.
