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HACTEHA [7]
3 years ago
8

Final Temperature in Heating Applesauce. A mixture of 454 kg of applesauce at 10°C is heated in a heat exchanger by adding 12130

0 kJ. Calculate the outlet tem perature of the applesauce. (Hint: In Appendix A.4, a heat capacity for applesauce is given at 32.8C. Assume that this is constant and use this as the average com)
Chemistry
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer:

T_f = 76.46°C

Explanation:

Given data:

Mass of mixture = 454 kg

Initial temperature is 10°C

Heat added is Q = 121300 kJ

Heat capacity (Applesuace) at 32.8°C is 4.02kJ/kg K

From heat equation we have

Q = mCp(T_f -T_i)

\frac{Q}{mCp} = (T_f -T_i)

T_f = T_i + \frac{Q}{mCp}

Putting all value to get required final temperature value

T_f = \frac{121300}{454\times 4.02} + 10

T_f = 76.46°C

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3 0
3 years ago
Read 2 more answers
A 48.3 mL sample of gas in a cylinder is warmed from 22 °C to
goldenfox [79]

Answer:

58.94 mL

Explanation:

V1 = 48.3 mL             V2 = v mL

T1 = 22 degree celsius OR 295 k         T2 = 87 degree celsius OR 360 k

We will use the gas equation:

PV = nRT

Since the Pressure (p) , number of moles (n) and the universal gas constant(R) are all constants in this given scenario,

we can say that

V / T = k , (where k is a constant)

Since this is the first case,

V1 / T1 = k --------------------(1)

For case 2:

Since we have the same constants, the equation will be the same

V / T = k (where k is the same constant from before)

V2 / T2 = k (Since this is the second case) ------------------(2)

From (1) and (2):

V1 / T1 = V2 / T2

Now, replacing the variables with the given values

48.3 / 295 = v / 360

v = 48.3*360 / 295

v = 58.94 mL

Therefore, the final volume of the gas is 58.94 mL

4 0
3 years ago
Whitney's lung capacity was measured as 3.3 l at a body temperature of 37 ∘c and a pressure of 746 mmhg . how many moles of oxyg
myrzilka [38]

the ideal gas equation is PV=nRT  
 where P=pressure  
 V=Volume  
 n=no. of moles  
 R=universal gas constant  
 T=temperature  
 The universal gas constant (R) is 0.0821 L*atm/mol*K    
 a pressure of 746 mmhg =0.98 atm= 1 atm (approx)   
 T=37 degrees Celsius =37+273=310 K (convert it to Kelvin by adding 273)    
 V=0.7 L (only getting oxygen, get 21% of 3.3L)    
 Solution:  
 (1 atm)(0.7 L)=n(0.0821 L*atm/mol*K)(310 K)  
 0.7 L*atm=n(25.451 L*atm/mol)  
 n=0.0275 mole   
 Answer:   
n=0.0275 mole of oxygen in the lungs.
4 0
3 years ago
Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of sodium sulfide and iron(II) nitrate
Luda [366]

Answer:

Fe^2+(aq) + S^2-(aq) --------> FeS(s)

Explanation:

First let us look at the molecular equation;

Na2S(aq) + Fe(NO3)2(aq) --------> FeS (s) + 2NaNO3(aq)

Now, the net ionic equation usually shows the most important reaction that took place, in this case, the formation of the FeS precipitate.

Hence, ionically;

Fe^2+(aq) + S^2-(aq) --------> FeS(s)

8 0
3 years ago
Help have no idea what to do
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Number one is true !!!!!!????!???????????!!!!!!!!!!!!
8 0
3 years ago
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