Question

Final Temperature in Heating Applesauce. A mixture of 454 kg of applesauce at 10°C is heated in a heat exchanger by adding 121300 kJ. Calculate the outlet tem perature of the applesauce. (Hint: In Appendix A.4, a heat capacity for applesauce is given at 32.8C. Assume that this is constant and use this as the average com)

Answer 1

Answer:

$T_f = 76.46°C$

Explanation:

Given data:

Mass of mixture = 454 kg

Initial temperature is 10°C

Heat added is Q = 121300 kJ

Heat capacity (Applesuace) at 32.8°C is 4.02kJ/kg K

From heat equation we have

$Q = mCp(T_f -T_i)$

$\frac{Q}{mCp} = (T_f -T_i)$

$T_f = T_i + \frac{Q}{mCp}$

Putting all value to get required final temperature value

$T_f = \frac{121300}{454\times 4.02} + 10$

$T_f = 76.46°C$