<span>Data:
Initial velocity upward: Vo = 5.00 m/s ,
Initial position: h = 40.0 m above the ground
Type of motion: free fall.
A) Compute the position of the sandbag at a time 1.05 s after its release.
Equation: y = h + Vo*t - g*(t^2) / 2
y = 40.0 m + 5.00 m/s * 1.05s - (9.8 m/s^2) * (1.05 s)^2 / 2 = 39.8 m
B)Compute the velocity of the sandbag at a time 1.05 s after its release.
Equation: Vf = Vo - g*t
=> Vf = 5.00 m/s - (9.8m/s^2) * (1.05 s) = - 5.29 m/s
Negative sign means that the sandbag is going down.
c) How many seconds after its release will the bag strike the ground?
Equation:
y = yo + Vo*t - g*(t^2) / 2
0 = 40.0 + 5.00t - 4.9 t^2
=> 4.9 t^2 - 5t - 40 = 0
Use the quadratic formula and you get: t = 3.41 s
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Not that I know of. Sometimes watching something, listening to music, reading a book, or talking can help. There are some homeopathic remedies that can help as well.
Answer:

so each bulb brightness becomes half of its given or indicated power

so both bulb will glow same power as indicated
Explanation:
Let the indicated power on the bulbs is given as P and its rated voltage is V
so here resistance of each bulb is given as

now if the two bulbs are connected in series so we will have


now the current in the circuit is given as


now brightness of each bulb is given as


so each bulb brightness becomes half of its given or indicated power
Now if the two bulbs are connected in parallel
then the net voltage across each bulb is "V"
so we will have

so both bulb will glow same power as indicated
You will get 20460000 as your answer which is broken down into, 2.046 x 10^7 as your number has to be between 1-10.