Answer:
T=1.384×10⁶seconds
Explanation:
Given data
p (Intensity)=1.30 kw/m²
E (Energy)=1.8×10⁹ J
A (Area)=1.00 m²
T (Time required)=?
Solution
E=PT ................eq(i)
where E is energy
P is radiation power
T is time
Radiating Power is given as
P=pA
Where p is intensity
A is Area
Put P=pA in eq(i) we get
E=pAT
T=E/pA

ANSWER:
[i] False.
[ii] Work is the product of force and displacement.
REASONS:
[i] As we already know that temperature is a measure of the average kinetic energy of the particles in an object.
[ii] W = FS
Answer:
G M m / R^2 = m v^2 / R centripetal force equals gravitational force
1/2 m v^2 = G M m / R = KE rearranging the above equation
T = 2 pi R / v time for one revolution (period)
T^2 = 4 pi^2 R^2 / v^2
From the very first equation v^2 = G M / R
so T^2 = 4 pi^2 R^3 / (G * M)